Answer:
The initial vertical velocity is zero, u = 0 m/s
Explanation:
Given;
height of the table, h = 0.55 m
horizontal distance traveled by the tennis, x = 0.12 m
Apply the following kinematic equation;
h = ut + ¹/₂gt²
where;
u is the initial vertical velocity = 0, since the tennis ball rolled off the edge of a table.
h = ¹/₂gt²
The time to fall from the vertical height is given by;
The initial horizontal velocity of the tennis is given by;
x = vₓt
vₓ = x / t
vₓ = (0.12) / (0.335)
vₓ = 0.358 m/s
Therefore, the initial vertical velocity is zero, u = 0 m/s and initial horizontal velocity, vₓ is 0.358 m/s
Answer:
0.8c and -0.14c
Explanation:
The first fragment will have a speed of +0.5c respect of a frame of reference moving at +0.5c
Lest name v the velocity of the frame of reference, and u' the velocity of the object respect of this moving frame of reference.
The Lorentz transform for velocity is:
u = (u' + v) / (1 + (u' * v) / c^2)
u = (0.5c + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = 0.8c
The other fragment has a velocity of u' = -0.6c respect of the moving frame of reference.
u = (-0.6v + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = -0.14c
Answer:
Refractive index of unknown liquid = 1.56
Explanation:
Using Snell's law as:
Where,
is the angle of incidence ( 65.0° )
is the angle of refraction ( 53.0° )
is the refractive index of the refraction medium (unknown liquid, n=?)
is the refractive index of the incidence medium (oil, n=1.38)
Hence,
Solving for ,
Refractive index of unknown liquid = 1.56
Answer:
besides a reduction in friction, the only way to increase the amount of work output of a machine is to Increase the work input
i
Explanation:
Answer:
4m/s^2
Explanation:
mass(m)=20 kg
force=80 N
acceleration (a)=?
Therefore,
Force = mass * acceleration
80 = 20*a
a=80/20
=4m/s^2
