In a hydrolysis reaction between a strong acid and a weak base, the salt formed will have a pH less than 7. By virtue of this phenomenon between <span>weak bases and strong acids</span>, the anion of the strong acid will fail to attract the hydrogen ion<span>, while the cation from the weak base will donate a </span>proton<span> to the water forming a hydronium ion</span><span>.
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<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.
<span>ρwAd1g = Mg</span>
ρw<span>Ad2g = (M + m) g</span>
<span>d2∕d1 = (M + m)/g</span>
m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>
This means that Bubba’s mass is 120 kg.
The displacement vector (SI units) is
![\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Br%7D%20%3DAt%5Chat%7Bi%7D%2BA%5Bt%5E%7B3%7D-6t%5E%7B2%7D%5D%5Chat%7Bj%7D)
The speed is a scalar quantity. Its magnitude is
Answer: At√(t⁴ - 12t³ + 36t² + 1)
The radius of the prop blade of an airplane is determined as 4.25 m.
<h3>
Radius of the prop blade</h3>
The radius of the prop blade of an airplane is calculated as follows;
a = v²/r
where;
- v is the linear speed
- r is the radius of the prop blade
- a is the centripetal acceleration
r = v²/a
r = (875²)/(180,000)
r = 4.25 m
Thus, the radius of the prop blade of an airplane is determined as 4.25 m.
Learn more about centripetal acceleration here: brainly.com/question/79801
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