X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
Answer:
8
Step-by-step explanation:
Answer:
repost it, I cant see all of the question
Answer:
<u>x = √51</u>
Step-by-step explanation:
The given figure is a <u>right triangle</u>.
<u>Using the Pythagorean Theorem to find x</u>
- (Altitude 1)² + (Altitude 2)² = (Hypotenuse)²
- (7)² + x² = (10)²
- 49 + x² = 100
- x² = 51
- <u>x = √51</u>
C. 4.45 cm. you take the circumference and divide it by pi to find the diameter
