the pressure in a 100ml container is 150.2 kpa at 500k. that pressure is adjusted to 101.3kpa, what is the new temperature
1 answer:
The new temperature is 337.21 K when the pressure was reduced to 101.3 kPa from 150.2 kPa at 500 K.
Explanation:
Data given:
volume of the container = 100 ml
initial pressure on the container P1 = 150.2 kPa
Initial temperature of the container, T1 = 500 K
final temperature of the container, T2 = ?
Final pressure on the container P2 = 101.3 kPa
from the data provided, we will use Gay Lussac's law to calculate the final temperature:
rearranging the equation,
T2 =
Putting the values in the equation:
T2 =
T2 = 337.21 K
thus, the final temperature of the container is 337.21 K
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As the y-intercept increases, the graph of the line shifts up;
As the y-intercept decreases, the graph of the line shifts down
Explanation:
There are two ways to think about this problem. The first way would be the graphical approach:
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- y-axis is the vertical axis;
- if we change the point at which the line crosses the y-axis, we either shift it upward for a higher y-intercept or downward for a lower y-intercept.
Now, thinking algebraically, a line has the following equation in a general form:
The y-intercept is essentially obtained when x = 0, then:
y = b:
- if we increase b value, the y value increases, so the graph shifts upward;
- if we decrease b value, the y value decreases, so the graph shifts downward.