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Juli2301 [7.4K]

3 years ago

13

An object is moving in a straight line along the y axis. As a function of time, its position is given by the equation y=3.0+4.8x

+6.4x ,What is the velocity of the object as a function of time?
What is the acceleration of the object as a function of time?

1 answer:

romanna [79]3 years ago

5 0

Answer:

Explanation:

<u>Instant Velocity and Acceleration </u>

Give the position of an object as a function of time y(x), the instant velocity can be obtained by

$v(x)=y'(x)$

Where y'(x) is the first derivative of y respect to time x. The instant acceleration is given by

$a(x)=v'(x)=y''(x)$

We are given the function for y

$y(x)=3.0+4.8x +6.4x^2$

Note we have changed the last term to be quadratic, so the question has more sense.

The velocity is

$v(x)=y'(x)=4.8+12.8x$

And the acceleration is $a(x)=v'(x)=12.8$

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If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.

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8 0

3 years ago

The 0.5kg soccer ball moves toward the net with a force of 4N. What is its acceleration?

Eduardwww [97]

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8 m/s²

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Given,

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To find : -

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2 years ago

When an average force F is exerted over a certain distance on a shopping cart of mass m, its kinetic energy increases by 12mv2.

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Answer:

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Explanation:

Given that

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$\Delta KE=\dfrac{1}{2}mv^2$

we know that

Work done by all the forces =change in the kinetic energy

a)

Lets distance = d

We know work done by force F

W= F .d

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$d=\dfrac{1}{2F}mv^2$

b)

If the force become twice

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2ΔKE = ΔKE'

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3 years ago

Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.

scoundrel [369]

Answer

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b) when air density decreased linearly to zero.

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2 years ago