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Mademuasel [1]
3 years ago
14

(a) What is the magnitude of the tangential acceleration of a bug on the rim of a 12.5-in.-diameter disk if the disk accelerates

uniformly from rest to an angular speed of 75.0 rev/min in 3.80 s
Physics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

Explanation:

Given:

d=12.5in=0.3175m

r=d/2=0.3175/2=0.15875m

ωf=75rev/min=7.85rad/s

t=3.80s

The angular acceleration

\alpha = \frac{\omega _f - \omega _i}{t}=\frac{7.85-0}{3.80}=2.07rad/s^2

Tangential acceleration

\alpha =r\alpha =0.15875\times  2.07=0.33m/s^2

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An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 J of gravitational potential energy. How high did the hike
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Answer:

599 meters is the answer rounded to the nearest whole number and 599.489795918 meters is the complete answer

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In the middle of a thunderstorm, a lightning bolt flashes. It takes Roberto 5 seconds to
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Answer:

 v = 344.1 m / s    

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Explanation:

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we calculate

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we calculate

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           d = 1720.5 m

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3 years ago
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