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bezimeni [28]
2 years ago
9

cecily is inflating her bicyble tyre with the pump below. when she pushes the plunger down, it is moving against a force applief

d by the air inside the cynlinder. this means that the plunger is doing ___
Physics
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

"work against the force of the air in the tire"

The air in the tire provides a force opposing the force of the air provided by the plunger.

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In a tug of war, when one team is pulling with a force of 85 N and the other 40 N, what is the net
olya-2409 [2.1K]
85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards
4 0
3 years ago
HURRY PEASE what happens to current when there is a diode on the circuit and why?
kolbaska11 [484]

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

Explanation:

6 0
3 years ago
What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms? A) 2.9 V B) 11.8 V C) 24.2 V D) 111.6 V
maks197457 [2]

V = I · R  =  (6.2 A) · (18 Ω) =  111.6 volts  (D)
7 0
3 years ago
Read 2 more answers
If a nearsighted person has a far point df that is 3.50 m from the eye, what is the focal length f1 of the contact lenses that t
Anastaziya [24]

Answer:

f1 = -3.50 m

Explanation:

For a nearsighted person an object at infinity must be made to  appear  to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.

∴ v = -3.5 m

Using mirror formula,

i/f1 = 1/v + 1/u

Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u =         object distance = at infinity(∞) = 1/0

∴ 1/f1 = (1/-3.5) + 1/infinity

  Note that, 1/infinity = 1/(1/0) = 0/1 =0.

∴ 1/f1 = 1/(-3.5) + 0

  1/f1 = 1/(-3.5)

Solving the equation by finding the inverse of both side of the equation.

∴ f1 = -3.50 m

 Therefore a converging lens of focal length  f1 = -3.50 m

would be needed by the person to see an object at infinity clearly

8 0
3 years ago
You’re speeding at 85 km/hr when you notice that you’re only 10 m behind the car in front of you,
solmaris [256]
Your position in meters will, measured relative to the starting point of the car behind you, be 
x1(t) = 10 + 23.61 t - 1/2 4.2 t^2 
his position will be 
x2(t) = 16.67 t 
Hence at any time the separation s(t) will be 
s(t) = x1(t) - x2(t) = 10 + 6.94 t -2.1 t^2 
Now I assume you mean that you will decelerate UNTIl you are driving at the legal speed limit (60 km/h). That will take you: 
16.67 m/s = 23.61m/s - 4.2 m/s^2 * t 
t = 1.65 seconds 
What is the separation at that time? If it is still greater than zero, there will be no collision: 
s(1.65) = 10 + 6.94 *1.65 -2.1 (1.65)^2 = 15.73 meters. 
Hence you will NOT collide. The 1.65 s you calculated was the time needed to brake to the speed of 60 km/h. 
7 0
3 years ago
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