Henderson-Hasselbalch equation relates the pH with the dissociation constant of the acid. The pH of the buffer solution will be 3.90.
<h3>What is the Henderson-Hasselbalch equation?</h3>
The Henderson-Hasselbalch equation is used to calculate the pH or the concentration of the conjugate base and acid.
The Henderson-Hasselbalch equation can be given as,
pH = pKa + log [A⁻] ÷ [HA]
The dissociation reaction is given as,
HA⁺ + H2O ⇌ H3O⁺ + A⁻
NaA → Na⁺ + A⁻
For this first pKa is calculated as:
pKa = - log (1. 0 x 10⁻⁴)
Substituting the value of pKa in Henderson-Hasselbalch equation pH is determined as:
pH = - log (1. 0 x 10⁻⁴) + log [0.08] ÷ [0.1]
= 4 + (-0.0969)
= 3.90
Therefore, 3.90 is the pH of the solution.
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Answer:
Mg(s) + 2H⁺(aq) ⟶ Mg²⁺(aq) + H₂(g)
Explanation:
A net ionic equation shows all the ionic substances as ions and shows the correct state of each substance.
B. is wrong. HCl ionizes in aqueous solution into H⁺ and Cl⁻.
C. is wrong. Mg²⁺ is not a solid. It is an aqueous ion.
D. is wrong. The equation needs 2H⁺(aq) to be balanced.
We know that the molar mass of Al is 27 g/mol.
27 g Al* (1 mol Al/ 27 g Al)= 1 mol Al.
The final answer is 1 mol Al~
Answer:
46.07
Explanation:
im not 100 sure this is right almost tho
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