Answer:
27.7 g
Explanation:
To solve this problem we use the definition of <em>molarity</em>:
From the problem we're given M = 2.5 M and volume = 0.100 L. We use the above formula and <u>calculate the required moles of calcium chloride</u> (CaCl₂):
Finally we use the<em> molecular weight</em> of calcium chloride to <u>calculate the required mass</u>:
- 0.25 moles CaCl₂ * 110.98 g/mol = 27.745 g CaCl₂
Rounding to the nearest tenth of a gram the answer is 27.7 g.
Answer:
#2 Empirical formula _Na3S4O9____
Molecular formula ___Na6S8O18__
Explanation:
<u>Answer:</u>
<u>For a:</u> The isotopic symbol of the above atom will be 
<u>For b:</u> The isotopic symbol of the above atom will be 
<u>For c:</u> the isotopic symbol of the above atom will be 
<u>Explanation:</u>
The isotopic representation of an atom is: 
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
Atomic number of iodine = 53
Mass number of iodine = 131
Symbol of iodine = I
The isotopic symbol of the above atom will be 
- <u>For b:</u> Iridium-192
Atomic number of iridium = 77
Mass number of iridium = 192
Symbol of iridium = Ir
The isotopic symbol of the above atom will be 
- <u>For c:</u> Samarium-153
Atomic number of samarium = 62
Mass number of samarium = 153
Symbol of samarium = Sm
The isotopic symbol of the above atom will be 
Answer:
Solid
Explanation:
Is this a trick question?
If not, solid.