Answer:
0.99 seconds
Explanation:
The problem depicts a simple harmonic motion.
Now, from Hooke's law,
The spring constant is given as;
k =F/x
where:
x is the displacement of the spring's end from its equilibrium position
F is the restoring force exerted by the spring on that end
From the question, F = 20N while x = 10cm = 0.1m. Thus,
K = 20/0.1 = 200 N/m
Now, time to take for the mass to return to its starting point is a period
The period oscillation of the mass is given as;
T = 2π√m/k
Where m = mass = 5kg
T = 2π√(5/200)
T = 0.99 s
