What is a 2.48x10^3 atm ____mm Hg

1 answer:

7 0

I'm assuming that you want to covert atmospheres into mmHg.

mmHg is exactly like torr: there are 760 of them in an atmosphere.

The conversion would be 760 mmHg = 1 atm

Knowing this, simply multiply 2.48 * 10^3 by 760:
2.48 * 10^3 * 760 = 1,884,800 mmHg.

But wait! I'm assuming you probably meant to write 2.48 * 10^-3, since 1,884,800 is an awfully big number.

In that case:

2.48 * 10^-3 * 760 = 1.8848 mmHg

-T.B.

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If you burn 59.1 g of hydrogen and produce 528 g of water , how much oxygen is reacted

shtirl [24]

Hydrogen + oxygen --> water
59,1g + x = 528g
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8 0

3 years ago

If you have a 1500 g aluminum pot, how much heat energy is needed to raise its temperature by 100°C?

Nataly [62]

The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.

The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

Explanation:

The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.

So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).

Then, the heat energy required to raise the temperature will be

$q = m*c*del T = 1500 * 0.900 * 100 = 135000 = 135 kJ$

Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.

Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100 °C.

Then, the heat energy required to raise its temperature will be

$q = m*c*del T = 1500 * 0.385 * 100 = 57750 = 57.75 kJ$

And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.

So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.