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fredd [130]
3 years ago
13

Explain what is happening to an object that has an acceleration of 2ms-2

Physics
1 answer:
joja [24]3 years ago
7 0
It is gaining speed at the rate of 2 m/s per second.
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The driver of a car traveling at 23.1 m/s applies the brakes and undergoes a constant
Vsevolod [243]

Answer:

The tires make 125 revolutions before the car stops

Explanation:

Circular and Linear Motion

A tire rotates around a fixed point and the tire when in contact with the ground, drives a vehicle in a linear path. This is an example of a relationship between both types of movements that can be taking place simultaneously.

The car is moving with an initial speed of v_o=23.1\ m/s and then breaks at a=-1.03\ m/s^2 until it stops. We can compute the time take to stop by using

\displaystyle v_f=v_o+a.t

Solving for t

\displaystyle t=\frac{v_f-v_o}{a}

Putting in numbers

\displaystyle t=\frac{0-23.1}{-1.03}

\displaystyle t=22.427\ sec

Now, let's transfer this information to the circular motion. We know the tangent speed is

\displaystyle v_t=w.r

Being w the angular speed and r the radius of the circle, in this case, the tires. The tangent speed is the same as the speed of motion of the car. It gives us the initial angular speed

\displaystyle w_o=\frac{v_t}{r}

\displaystyle w_o=\frac{23.1}{0.33}=70\ rad/s

When the circular motion is not uniform, i.e. there is angular acceleration \alpha, the angular speed is a function of time

\displaystyle w=w_o+\alpha t

We can compute the angular acceleration knowing the final angular speed is zero when the car stops.

\displaystyle \alpha=\frac{w-w_o}{t}=\frac{0-70}{22.427}

\displaystyle \alpha=-3.121\ rad/s^2

The rotation angle is also a function of time as shown

\displaystyle \theta=w_o\ t+\frac{\alpha t^2}{2}

Using the given and computed values

\displaystyle =70(22.427)-\frac{3.121(22.427)^2}{2}

\displaystyle \theta =784.95\ rad

Knowing each revolution is 2\pi radians, the number of revolutions is

\displaystyle n=\frac{\theta }{2\pi}=125\ rev

The tires make 125 revolutions before the car stops

8 0
3 years ago
How long does it take the baton to complete one spin
sweet [91]

The time it takes the baton to complete one spin will be 0.56 s. Option B is correct.

<h3>What is centripetal acceleration?</h3>

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.

The entire question is;

"How long does it take the baton to complete one spin?

A twirler’s baton is 0.76 m long and spins around its center. The end of the baton has a centripetal acceleration of 47.8 m/s2.

a.0.31 s

b.0.56 s

c.4.3 s

d.70 s"

The given data in the problem;

Length of baton,L = 0.76 m

Centripetal acceleration,\rm F_c=47.8 \ m/s^2

The centripetal acceleration is found by;

a= \frac{4 \pi^2R}{T^2}

Substitute the given value:

\rm 47.82= \frac{4 \pi^2\times 0.38}{T^2} \\\\   47.82\times T^2 = 4(3.14)^2 \\\\T = 0.56 s

The time it takes the baton to complete one spin will be 0.56 s.

Hence option B is correct.

To learn more about centripetal acceleration, refer to the link;

brainly.com/question/17689540

#SPJ1

8 0
2 years ago
edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
Naily [24]

The displacement of Edward in the westerly direction is determined as 338.32 km.

<h3>What is displacement of Edward?</h3>

The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.

The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰

The displacement is the side of the triangle facing 150⁰ = R

R² = a² + b² - 2abcosR

R² = 150² + 200²  - (2x 150 x 200)xcos(150)

R² = 62,500 - (-51,961.52)

R² = 114,461.52

R = 338.32 km

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
1 year ago
Which statement did Kepler’s investigations of the movement of the planets explain?
wlad13 [49]

Answer:

It’s the fourth one :)

Explanation:

7 0
2 years ago
Read 2 more answers
Which part of the drum vibrates when it produces sound?
SVETLANKA909090 [29]

Explanation:

For example, when a drum is struck, the flexible skin (sometimes called a membrane) of the drum vibrates. The compression and expansion of the air on either side of the vibrating membrane produces differences in air pressure. The pressure differences generate a sound wave that propagates outward from the drum surface.

4 0
3 years ago
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