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3 years ago

Explain what is happening to an object that has an acceleration of 2ms-2

Physics

1 answer:

joja [24]3 years ago

7 0

It is gaining speed at the rate of 2 m/s per second.

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1. Astronomical observatories have been available since ancient times, and many cultures set aside special sites for astronomica

nydimaria [60]

Answer:

e telescopes

Explanation:

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4 0

3 years ago

A propagating wave in space with electric and magnetic components. These components oscillate at right angles to each other. It

zimovet [89]

Answer:

electromagnetic

Explanation:

8 0

3 years ago

Read 2 more answers

(a) What is the entropy change of a 14.6 g ice cube that melts completely in a bucket of water whose temperature is just above t

Alex73 [517]

Answer:

a) 17.81 J/K

b) 33.325 J/K

Explanation:

The expression to use here is the following:

ΔS = Q/T

Where:

Q: heat released or absorbed

T: Temperature in K

Now, in order to do this, we need to gather the data. We know that the temperature in part a) is above the freezing temperature of water, which is 0 ° C or 273 K. and the mass of the ice cube is 14.6 g.

a) Using the water heat of fusion (Cause it's melting), we can calculated the heat released using the following expression:

Q = m * Lf

Lf = 333,000 J/kg

Solving for Q first we have:

Q = (14.6 / 1000) * 333,000

Q = 4,861.8 J

Now, the entropy change is:

ΔS = 4,861.8 / 273

ΔS = 17.81 J/K

b) In this part, we follow the same procedure than in part a) but using the water heat of boiling (Lv = 2,256,000 J/kg), the temperature of boiling which is 100 °C (or 373 K) and the mass of 5.51 g (0.00551 kg)

Calculating the heat:

Q = 0.00551 * 2,256,000 = 12,430.56 J

Now the entropy change:

ΔS = 12,430.56 / 373

ΔS = 33.325 J/K

8 0

3 years ago

Which medium is more denser diamond or water

kenny6666 [7]

Diamond, it's just asking if it's heavier than water

7 0

3 years ago

Part A By what distance do two objects carrying 1.0 C of charge each have to be separated before the electric force exerted on e

aalyn [17]

Answer:

Part A: 4.74×10⁴ m

Part B: 0.000211 C

Explanation:

Part A:

From coulombs law,

F = kq²/r²........................ Equation 1

Note: The two object are carrying equal charges.

Where F = Electric force, q = charge, r = distance of separation, k = proportionality constant

Given: F = 4.0 N, q = 1.0 C,

Constant: k = 1/4πe₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 1,

4 = 9×10⁹(1²)/r²

r² = (9×10⁹)/4

r² = 2.25×10⁹

r = √(2.25×10⁹)

r = 4.74×10⁴ m.

Part 2:

F = kq²/r²

Making q the subject of the equation

q = √(Fr²/k)........................... Equation 2

Where: F = 4.0 N, r = 1.0 m, k = 9×10⁹ Nm²/c²

Substituting these values into equation 2

q = √(4×1²/(9×10⁹ )

q = 2.11/10⁴

q = 0.000211 C.

6 0

3 years ago