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Sergio [31]
3 years ago
5

The cement bag shown in the figure has a mass of 50 kg and the small pulley has a mass of 2 kg. If the cement bag is pulled upwa

rds with an acceleration of 2 m/s^2, find the force F pulling the rope.

Physics
1 answer:
GuDViN [60]3 years ago
3 0

For the cement bag we can say as per its force diagram we will have

2F - mg = ma

here we will have

m = 50 kg

a = 2 m/s^2

now we will have

F = \frac{mg + ma}{2}

now plug in all data

F = \frac{50(9.8 + 2)}{2}

F = 295 N

so the pulling force will be 295 N

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A charged particle of mass m = 5.00g and charge q = -70.0μC moves horizontally to the right at a constant velocity of v = 30.0 k
pychu [463]

Answer:

The magnitude of the force, B = 5 Tesla, Up (North) direction

Explanation:

Magnetic force F= Eq where Electric field, E = 750 NC

and charge, q = -70 μC = -7 ×10^{-5}C

F = 750 ×  -7 ×10^{-5}

F = 0.0525

But F = qvB; B = \frac{F}{qv}

where B is the magnetic field

= 0.0525 ÷ ( -7 ×10^{-5} × 30)

B = 5.0 Teslas

The force on a negative charge is in exactly the opposite direction to that on a positive charge.

Hence the direction of the charge is up (North).

8 0
3 years ago
Read 2 more answers
Describe how the mass, luminosity, surface temperature, and radius of main-sequence stars change in value going from the “bottom
Sladkaya [172]

Answer:

1. Least massive stars are the coolest and least luminous, lower right of main sequence, on HR diagram.  

2. Most massive are the hottest and most luminous, upper left of main sequence on Hr Diagram.  

3. The radius of stars are related to their sprectral type. having the O being the hottest upper left and M being the coolest bottom right.

4 0
3 years ago
You are working at a company that manufactures electri- cal wire. Gold is the most ductile of all metals: it can be stretched in
Alona [7]

Explanation:

We know that the relation between volume and density is as follows.

      Volume = \frac{\text{mass}}{\text{density}}

So,       V = \frac{10^{-3}}{19.3 \times 10^{3} kg/m^{3}}

               = 5.181 \times 10^{-8} m^{3}

Now, we will calculate the area as follows.

      Area = \frac{\text{volume}}{\text{length}}

               = \frac{5.181 \times 10^{-8} m^{3}}{2.4 \times 10^{3}}

               = 2.15 \times 10^{-11} m^{2}

Formula to calculate the resistance is as follows.

         R = \rho \frac{l}{A}

             = \frac{2.44 \times 10^{-8} \times 2400}{}2.15 \times 10^{-11}}

             = 2.71 \times 10^{6} ohm

Thus, we can conclude that the resistance of given wire is 2.71 \times 10^{6} ohm.

4 0
3 years ago
1 point
Sav [38]

Answer:

388.5J

Explanation:

Given parameters:

Weight  = 70N

Height  = 5.55m

Unknown:

Gravitational potential energy at the top of the ladder  = ?

Solution:

The gravitational potential energy is the energy due to the position of the body.

  Gravitational potential energy  = Weight x height

So;

 Gravitational potential energy  = 70 x 5.55 = 388.5J

8 0
2 years ago
A home run is hit in such a way that the baseball just clears a wall 21m hgh located 130m from home plate the ball is hit at an
svlad2 [7]

Answer:

see the attachment

Explanation:

take coordinate system correctly. use formulas of projectile motion

Download pdf
3 0
3 years ago
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