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Sergio [31]
2 years ago
5

The cement bag shown in the figure has a mass of 50 kg and the small pulley has a mass of 2 kg. If the cement bag is pulled upwa

rds with an acceleration of 2 m/s^2, find the force F pulling the rope.

Physics
1 answer:
GuDViN [60]2 years ago
3 0

For the cement bag we can say as per its force diagram we will have

2F - mg = ma

here we will have

m = 50 kg

a = 2 m/s^2

now we will have

F = \frac{mg + ma}{2}

now plug in all data

F = \frac{50(9.8 + 2)}{2}

F = 295 N

so the pulling force will be 295 N

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A ball is thrown w a speed of 30m/s at an angle of 10. When is the vertical component of the velocity equal to zero
irga5000 [103]

Now the vertical velocity of the ball thrown at an angle 10° is given as

Voy(initial vertical velocity)= 30m/s x sin 10

Voy(initial vertical velocity)= 5.2m/s

Now the ball is decelerating with an acceleration due to gravity equivalent to 9.8m/s^2.

Let Vy be the final velocity and that is equal to zero in this case.

Now

Vy= Voy- tx9.8

Where t is the time at which the vertical velocity becomes 0.

Substituting the values we get

0= 5.2-tx9.8

9.8t=5.2

t=0.53 secs



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4 0
3 years ago
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Calculate the molar heat capacity of a monatomic non-metallic solid at 298K which is characterized by an Einstein temperature of
Ratling [72]

Answer: 5.5 ×10^-2 ×3R. Non metals that are solid at room temperature has mono atomic atoms that has only 3 translational modes.

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3 0
2 years ago
A bee flies at a constant rate of 5 m s until it notices a flower. It then comes to rest in 5 seconds. Find the acceleration of
JulsSmile [24]
Vi=5m/s because that was the speed before it started decelerating
Vf=0m/s because it says it comes to rest
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3 0
2 years ago
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A small cork is charged to +4.50 mC. Find the number of excess elementary charges (protons or electrons)
Irina-Kira [14]

Answer:

The third choice: 2.81*10^{16} \: \text{protons}

Explanation:

The cork is positively charged, therefore we know tat there must be excess of positively charged protons present.

The charge p^+ of a proton is

p^+ = +1.6*10^{-19}C;

therefore, the number n that makes up a charge of +4.5mC is

n = \dfrac{+4.5mC}{+1.6*10^{-19}C}  = \dfrac{+4.5*10^{-3}C}{+1.6*10^{-19}C}

\boxed{n =2.81*10^{16} \: \text{protons}}

which is the 3rd choice.

7 0
3 years ago
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