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Anarel [89]
3 years ago
8

Whound bus is travelling at 60 miles per hour on rte 95 going south west (for example travelling

Physics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.

Explanation:

Given that,

Speed = 60 miles/hour

Direction = south west

Let the south in y axis and west in x axis.

Angle between x and y will be θ.

The component of speed is V_{x} of x axis and  V_{y} of y axis.

\vect{V}=\vec{V_{x}i}+\vec{V_{y}j}

Where,

V_{x}=|\vec{V}|\cos\theta...(I)

V_{y}=|\vec{V}|\sin\theta....(II)

We know that,

The south west direction makes 45° with west direction in x axis.

(a). We need to calculate the velocity component in south direction

Using equation (I)

V_{x}=|\vec{V}|\cos\theta

Put the value into the formula

V_{x}=60\times\cos45

V_{x}=42.42\ miles/hour

(b). We need to calculate the velocity component in west direction

Using equation (II)

V_{x}=|\vec{V}|\sin\theta

Put the value into the formula

V_{x}=60\times\sin45

V_{x}=42.42\ miles/hour

Hence, The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.

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The burning of 1.0 g of coal produces 35 000 joules of energy. How many kcals are produced?
sergeinik [125]
I got the 1.0g of coal producves 35,000 joules which is also 8.36 kcals
8 0
3 years ago
What is the wavelength of a monochromatic light beam, where the photon energy is 2.70 × 10^−19 J? (h = 6.63 ×10^−34 J⋅s, c = 3.0
SOVA2 [1]

Answer:

Wavelength = 736.67 nm

Explanation:

Given

Energy of the photon = 2.70 × 10⁻¹⁹ J

Considering:

Energy=h\times frequency

where, h is Plank's constant having value as 6.63 x 10⁻³⁴ J.s

The relation between frequency and wavelength is shown below as:

c = frequency × Wavelength

Where, c is the speed of light having value = 3×10⁸ m/s

So, Frequency is:

Frequency = c / Wavelength

So,  Formula for energy:

Energy=h\times \frac {c}{\lambda}

Energy = 2.70 × 10⁻¹⁹ J

c = 3×10⁸ m/s

h = 6.63 x 10⁻³⁴ J.s

Thus, applying in the formula:

2.70\times 10^{-19}=6.63\times 10^{-34}\times \frac {3\times 10^8}{\lambda}

Wavelength = 736.67 × 10⁻⁹ m

1 nm = 10⁻⁹ m

So,

<u>Wavelength = 736.67 nm</u>

8 0
3 years ago
A steel cable with Cross Sectional Area 3.00cm² has an elastic limit of 2.40 x 10^8pascals. Find the maximum upward acceleration
bazaltina [42]

Answer:

Stress = F / A       force per unit area

A = 3.00 cm^2 = 3 E-4  m^2

F = 2.4E8 N/m^2 * 3E-4 m^2 = 7.2E4 N    max force applied

F/3 = 2.4E4 N  if force not to exceed limit   (= f)

f = M a

a = 2.4 E4 N / 1.2 E3 kg = 20 m / s^2      about 2 g

3 0
3 years ago
A violin with string length 32 cm and string density 1.5 g/cm resonates in its fundamental with the first overtone of a 2.0-m or
love history [14]

Answer:

T=1022.42 N

Explanation:

Given that

l = 32 cm ,μ = 1.5 g/cm

L =2 m  ,V= 344 m/s

The pipe is closed so n= 3 ,for first over tone

f=\dfrac{nV}{4L}

f=\dfrac{3\times 344}{4\times 2}

f= 129 Hz

The tension in the string given as

T = f²(4l²) μ

Now by putting the values

T = f²(4l²) μ

T = 129² x (4 x 0.32²)  x 1.5 x  10⁻³ x 100

T=1022.42 N

6 0
3 years ago
A 5 kg box drops a distance of 10 m to the ground. If 70% of the initial potential energy goes into increasing the internal ener
Elina [12.6K]

Answer:

Explanation:

From the given information:

The initial PE (PE)_i = m×g×h

= 5 kg × 9.81 m/s² × 10 m

= 490.5 J

The change in Potential energy P.E of the box is:

ΔP.E = P.E_f -P.E_i

ΔP.E = 0 - (PE)_i

ΔP.E = -P.E_i

If we take a look at conservation of total energy for determining the change in the internal energy of the box;

\Delta P.E + \Delta K.E + \Delta U = 0

\Delta U = -\Delta P.E - \Delta K.E

this can be re-written as:

\Delta U =- (-\Delta P.E_i) - \Delta K.E

Here, K.E = 0

Also, 70% goes into raising the internal energy for the box;

Thus,

\Delta U =(70\%) \Delta P.E_i-0

\Delta U =(0.70) (490.5)

ΔU = 343.35  J

Thus, the magnitude of the increase is = 343.35 J

7 0
3 years ago
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