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kifflom [539]
3 years ago
6

The burning of 1.0 g of coal produces 35 000 joules of energy. How many kcals are produced?

Physics
1 answer:
sergeinik [125]3 years ago
8 0
I got the 1.0g of coal producves 35,000 joules which is also 8.36 kcals
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A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the pot
denpristay [2]

Answer:

Part a)

V = 18.16 V

Part b)

P_r = 345 Watt

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

P_r = 345 Watt

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

\Delta V = E + i r

here we have

E = 12 V

i = 56 A

r = 0.11

now we have

\Delta V = 12 + (0.11)(56) = 18.16 V

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

P_r = i^2 r

P_r = 56^2 (0.11)

P_r = 345 W

Part c)

Rate of energy conversion into EMF is given as

P_{emf} = i E

P_{emf} = (56)(12)

P_{emf} = 672 Watt

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

V = E - i r

V = 12 - (56)(0.11)

V = 12 - 6.16 = 5.84 V

Part e)

now the rate of energy dissipation is given as

P_r = i^2 r

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7 0
3 years ago
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Lorico [155]

Answer:

540C.

Explanation:

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Q = CV          ----------(i)

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Where;

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Substitute these values into equation (i) as follows;

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F_{net} = F+W

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0 = K\Delta X -mg

We find the equilibrium for any location when

\Delta X = \frac{mg}{k}

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3 years ago
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