Question

The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s? s = StartFraction 3 Over 10 EndFraction m s = StartFraction 10 Over 3 EndFraction m m = StartFraction 3 Over 10 EndFraction s m = StartFraction 1 Over 30 EndFraction s. ⇔ HELP!!! I AM IN A DILEMMA!!!!

Answer 1

Answer:

s=3/10m

Step-by-step explanation:

option a) on edge

Answer 2

Answer:

$s = \frac{3}{10}m$

Step-by-step explanation:

Given

Mass = 30g

Spring Stretch = 9cm

Variation: Direct Variation

Required

Equation that relates the mass of the object, m, and the length of the spring, s

Let m represents mass and s represents length of the spring

Given that s varies directly to m;

This implies that

$s\ \alpha\ m$

Convert the above to an equation

$s = km$; where k is the constant of variation;

The next step is to solve for k

Divide both sides by m

$\frac{s}{m} = \frac{km}{m}$

$\frac{s}{m} = k$

$k = \frac{s}{m}$

From the given parameters;

when m = 30; s = 9.

$k = \frac{9}{30}$

Divide the numerator and denominator by 3

$k = \frac{3}{10}$

To get the equation that relates the mass of the object to the length of the spring

Substitute $k = \frac{3}{10}$ in $s = km$

This becomes

$s = \frac{3}{10}m$

Hence, the equation that relates the mass and length is $s = \frac{3}{10}m$