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3 years ago

A car takes 8s to increase its velocity from 10m/s to 30m/s.what is its average acceleration ?

Physics

1 answer:

DENIUS [597]3 years ago

7 0

Acceleration is 2.5 m/s^2V1-V0/t= a so 30 m/s - 10 m/s / 8s = 2.5 m/s^2

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The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1 x 103 Calories. If a

Luba_88 [7]

Answer:

$t = 70.13 hours$

Explanation:

As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy

so here we know that we have to use 7.56 lb of body fat

so here the total energy that is to be utilized is given as

$Q = (4.1 \times 10^3)(7.56)$

so we will have

$Q = 30996 Calorie$

now we know that runner expends the energy at rate of 1850 kJ/h

so we have

$E = 1850 \times 10^3 kJ/h$

so it is

$E = 0.44 \times 10^3 calorie/h$

now we know that time to burn this energy is given as

$t = \frac{Q}{E}$

$t = \frac{30996}{0.44 \times 10^3}$

$t = 70.13 hours$

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4 years ago

What does this equation mean FeDe=FrDr

rjkz [21]

Not exactly the best way to describe it but, it is used to calculate resistance of a lever as in the use of a pry bar or pulley. Technology used to increase output with little input.

3 0

3 years ago

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the drag force?

timurjin [86]

Answer: The drag force goes up by a factor of 4

Explanation:

The Drag Force equation is:

$F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}$ (1)

Where:

$F_{D}$ is the Drag Force

$C_{D}$ is the Drag coefficient, which depends on the material

$\rho$ is the density of the fluid where the bicycle is moving (air in this case)

$A_{D}$ is the transversal area of the body or object

$V$ the bicycle's velocity

Now, if we assume $C_{D}$ , $\rho$ and $A_{D}$ do not change, we can rewrite (1) as:

$F_{D}=C.V^{2}$ (2)

Where $C$ groups all these coefficients.

So, if we have a new velocity $V_{n}$ , which is the double of the former velocity:

$V_{n}=2V$ (3)

Equation (2) is written as:

$F_{D}=C.V_{n}^{2}=C.(2V)^{2}$

$F_{D}=4CV^{2}$ (4)

Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.

7 0

3 years ago

What’s the answer?? middle question

juin [17]

The new volume = 3 x 52.6 that’s because as the pressure decreases by 1/3 the volume increases x3

6 0

3 years ago

A kite is 100m above the ground. if there are 200m of string out what is the angle between the string and the horizontal? (assum

jeka57 [31]

Answer : The angle between the string and the horizontal is 30 degrees

Explanation: Imagine this a a triangle where the length of the string (200m) is the hypotenuse and the height of the kite is the opposite side (100m) .

Let the angle between the string and the horizontal be theta.

Now sin (Theta) = opposite side/hypotenuse

= 100/200 = 1/2

Therefore Theta = Sin ⁻¹ ( 1/2 )

Theta = 30 degrees

4 0

4 years ago