Answer:
about 602 milliseconds
Explanation:
The motion can be approximated by the equation ...
y = -4.9t^2 -22.8t +15.5
where t is the time since the arrow was released, and y is the distance above the ground.
When y=0, the arrow has hit the ground.
Using the quadratic formula, we find ...
t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))
= (22.8 ± √823.64)/(-9.8)
The positive solution is ...
t ≈ 0.60195193
It takes about 602 milliseconds for the arrow to reach the ground.
Answer:
636.619772368 A
Explanation:
= Torque = 
B = Magnetic field of Earth = 
A = Area
d = Diameter = 20 cm
Current is given by
The current is 636.619772368 A
This type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
<h3>
What is open system?</h3>
An open system is a type of system that has external interactions which means energy, or material transfers into or out of the system.
So we can conclude that this type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
Learn more about system here: brainly.com/question/14323743
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