Answer : The value of 
of the weak acid is, 4.72
Explanation :
First we have to calculate the moles of KOH.
Now we have to calculate the value of of the weak acid.
The equilibrium chemical reaction is:
Initial moles 0.25 0.03 0
At eqm. (0.25-0.03) 0.03 0.03
= 0.22
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[HK]}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BHK%5D%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
Therefore, the value of of the weak acid is, 4.72
Answer: The correct answer is d. The rates of the forward and reverse reactions are equal.
Explanation:
During a reversible reaction, a reaction that can occur to both sides of the equation, the chemical equilibirum is a state when the rates of reaction forward and reverse are equal, this means that the reaction never stops, it keep happening, but the conversion and decomposition rates are the same, and not necessarily the concentrations of reactants and products are equal.
Therefore, the correct answer is d. The rates of the forward and reverse reactions are equal.
Answer:
nuclear decay reactions and nuclear transmutation reactions
Explanation:
