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3 years ago

Give a example of scalar quantity

Physics

2 answers:

Bond [772]3 years ago

8 0

time , temperature and something that doesn't have direction

Serhud [2]3 years ago

7 0

speed, volume, mass, temperature and power

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Consider what happens at the moment when the block leaves the surface of the globe. Which of the following statements are correc

erma4kov [3.2K]

Answer:

Statement 1 and 3 are correct.

Explanation:

1. The mass moves downward, so the net acceleration of the block is straight downward.

2.The mass is sliding through the globe, so only the force of gravity is acting on the mass which pulls it in downward direction. The force of gravity has two components [mg sin∅] and [mg cos∅].

6 0

4 years ago

Read 2 more answers

EASY BRAINLIEST,PLEASE HELP!!

g100num [7]

Answer:

Explanation:

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3 years ago

A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hang

Romashka-Z-Leto [24]

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/ $s^{2}$ . The correct answer is 4.90 m/ $s^{2}$

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,

M( g + a) = m(g - a)

1(9.8 + a) = 3( 9.8 - a)

9.8 +a = 29.4 - 3a

collect the like terms

4a = 19.6

a = 19.6/4

a = 4.9 m/ $s^{2}$

Therefore, the cart accelerates to the right with a magnitude of 4.9 m/ $s^{2}$ . The correct answer is 4.90 m/ $s^{2}$

Learn more about dynamics here: brainly.com/question/24994188

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3 years ago

A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 3

SIZIF [17.4K]

Since the acceleration is uniform, we can calculate it from the data we are given:

a = (vf - vi)/2

where vf=33 m/s and vi=11 m/s

Then use Suvat's equation:

x(t) = vi*t + 0.5 * a * t

where t=20s

3 0

4 years ago

A child in a boat throws a 5.80-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 24.6kg and the ma

Sergio [31]

Answer:

-0.912 m/s

Explanation:

When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

$(m_c + m_b)v_b + m_pv_p = 0$

where $m_c = 24.6 kg, m_b = 39 kg, m_p = 5.8 kg$ are the mass of the child, the boat and the package, respectively. $, v_p = 10m/s, v_b$ are the velocity of the package and the boat after throwing.

$(24.6 + 39)v_b + 5.8*10 = 0$

$63.6v_b + 58 = 0$

$v_b = -58/63.6 = -0.912 m/s$

3 0

4 years ago