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amid [387]
2 years ago
14

Một ô tô bắt đầu chuyển động thẳng nhanh dần đều,sau 10 giây đạt vận tốc 72km/h.Gia tốc của ô tô là

Physics
2 answers:
NeTakaya2 years ago
7 0

Answer:

van

Explanation:

7nadin3 [17]2 years ago
6 0

Answer:

1

Explanation:

1

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A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is th
Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

        I_b  =  \frac{2 \pi * r * F }{ l *  \mu_o  *  I_a }

Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

=>      I_b  =  \frac{2 * 3.142  *  0.05 *  4 }{ 2.50  *  4\pi *10^{-7}  * 1000 }

=>      I_b  =  400 \ A

4 0
2 years ago
On the weather map, what does the symbol shown below represent?
Evgen [1.6K]

Answer:

wind speed i think where i live?

8 0
2 years ago
Compute the power output (watts) during one minute of treadmill exercise, given the following: Treadmill grade-10% Horizontal sp
erma4kov [3.2K]

Answer:

c. 981 watts

P=981\ W

Explanation:

Given:

  • horizontal speed of treadmill, v=100\ m.min^{-1}=\frac{5}{3} \ m.s^{-1}
  • weight carried, w=588.6\ N
  • grade of the treadmill, G\%=10\%

<u>Now the power can be given by:</u>

P=v.w

P=588.6\times\frac{5}{3} (where grade is the rise of the front edge per 100 m of the horizontal length)

P=981\ W

6 0
3 years ago
Could anyone help with this? :)
bonufazy [111]
I think the answer might be b
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3 years ago
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The moon orbits quite fast: it moves about 0.5 degrees per hour in the sky. In 24 hours it moves 13 degrees. The moon's observed motion eastward results from its physical motion of the moon along its orbit around the Earth. so I think its A .

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3 years ago
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