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3 years ago

6th grade help me pleaseee

Chemistry

2 answers:

chubhunter [2.5K]3 years ago

6 0

Answer:

D hope this helps

Explanation:

monitta3 years ago

3 0

Answer:

d. what will happen to the freezing point of the water if salt is added?

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What is the molality of a solution of 10 g NaOH in 500 g water? Molar mass NaOH = 40 g

umka2103 [35]

Explanation:

Moles of NaOH = 10g / (40g/mol) = 0.25mol.

0.25mol / 500g = 0.50mol / 1000g = 0.50mol/dm³.

The molarity is 0.50mol/dm³.

4 0

3 years ago

Fun fact! <3

victus00 [196]

Answer:

:O Fr? Bet let me go get them lol

3 0

3 years ago

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Automobile airbags contain solid sodium azide, NaN 3 , that reacts to produce nitrogen gas when heated, thus inflating the bag.

Yuri [45]

Answer: The value of work for the system is -935.23 J

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium azide = 16.5 g

Molar mass of sodium azide = 65 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium azide}=\frac{16.5g}{65g/mol}=0.254mol$

The given chemical equation follows:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of sodium azide produces 3 moles of nitrogen gas

So, 0.254 moles of sodium azide will produce = $\frac{3}{2}\times 0.254=0.381mol$ of nitrogen gas

To calculate volume of the gas given, we use the equation given by ideal gas, which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = ?

T = Temperature of the gas = $22^oC=[22+273]K=295K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = 0.381 moles

Putting values in above equation, we get:

$1.00atm\times V=0.381mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 295K\\\\V=\frac{0.381\times 0.0821\times 295}{1.00}=9.23L$

To calculate the work done for expansion, we use the equation:

$W=-P\Delta V$

We are given:

P = pressure of the system = $1atm=1.01325\times 10^5Pa$ (Conversion factor: 1 atm = 101325 Pa)

$\Delta V$ = change in volume = $9.23L=9.23\times 10^{-3}m^3$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$W=-1.01325\times 10^5Pa\times 9.23\times 10^{-3}m^3\\\\W=-935.23J$

Hence, the value of work for the system is -935.23 J

7 0

4 years ago

At equilibrium A. All reactions have ceased B. Only the forward reaction continues C. Only the reverse reaction continues D. Bot

vovangra [49]

Answer:

D)both the forward and reverse reactions continue.

Explanation:

Chemical equilibrium can be regarded as state whereby rate of the forward reaction is equal to rate of backward reaction. It should be noted that At equilibrium both the forward and reverse reactions continue.

8 0

3 years ago

Use the periodic to fill in the numbers in the electron configurations shown below.

puteri [66]

the answers are actually

C=2

D=6

E=1

4 0

3 years ago

Read 2 more answers