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3 years ago

How many moles are present in 1.2L of a 0.1 M NaCl solution?

Chemistry

1 answer:

____ [38]3 years ago

8 0

Answer:

0.12 mole.

Explanation:

From the question given above, the following data were obtained:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

Thus, we can obtain the mole of NaCl in the solution by using the above formula as follow:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity = mole /Volume

0.1 = mole of NaCl /1.2

Cross multiply

Mole of NaCl = 0.1 × 1.2

Mole of NaCl = 0.12 mole

Therefore, 0.12 mole of NaCl is present in the solution.

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4 years ago

WILL MARK BRANILEST

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Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

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4 years ago

Which of the following correctly describes a reaction that forms a disaccharide from two monosaccharides?

Dafna11 [192]

The answer that correctly describes a reaction that forms a disaccharide from two monosaccharides is Galactose + glucose = lactose.
Cellulose is not a disaccharide, glycogen is not a monosaccharide, and sucrose isn't either.

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3 years ago

Classify each of the following as a pure substance or a mixture. If a mixture, indicate whether it is homogeneous or heterogeneo

Mashutka [201]

Answer:

a) Heterogeneous mixture (b) Homogenous mixture (c) Pure substance (d) Pure substance

Explanation:

Homogenous mixtures contains mixture of substances with similar proportions while Heterogenous mixture contains substances with a varying proportion.

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3 years ago

How many particles are in 47.7 g of Magnesium? (Round the average

Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

$47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} )$ = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0

3 years ago