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Talja [164]
3 years ago
8

The exchange of matter between natural systems and human society affects the long-term functioning of both. How does the wolf-el

k case study from Yellowstone exemplify this point?
Answer it please. Any bad answers will go by-by.

am pro.

am pro questioner.
Chemistry
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

Yellowstone's northern range has been the focus of debate since the 1930s. ... of ecological functions, such as the addition of organic matter to the soil ... Some studies have shown a correlation between the presence of wolves and ... will change and how those changes will affect the Yellowstone system.

Explanation:

You might be interested in
Why does a chemical equation have to be balanced
Anton [14]
The chemical equation needs to be balanced so that it follows the law of conservation of mass.
5 0
3 years ago
A sample of 1.00 moles of oxygen at 50°C and 98.6 kPa, occupies what volume?
enyata [817]

Answer:

27.22 dm³

Explanation:

Given parameters:

number of moles = 1 mole

temperature= 50°C, in K gives 50+ 273 = 323K

Pressure= 98.6kpa in ATM, gives 0.973 ATM

Solution:

Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.

The ideal gas law is mathematically expressed as,

Pv=nRT

where P is the pressure of the gas

V is the volume

n is the number of moles

R is the gas constant

T is the temperature

Input the parameters and solve for V,

0.973 x V = 1 x 0.082 x 323

V= 27.22 dm³

5 0
3 years ago
A certain material has a mass of 12.48 g while occupying 12.48 cm3 of space. What is this material?
Salsk061 [2.6K]
This material has a density of 1 g/cm3.
(since 12.48 g/ 12.48 cm3 = 1 g/cm3)

Therefore, this material is water.
5 0
3 years ago
Read 2 more answers
Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe
Illusion [34]

Answer:

a. Kp=1.4

P_{A}=0.2215 atm

P_{B}=0.556 atm

b.Kp=2.0 * 10^-4

P_{A}=0.495atm

P_{B}=0.00995 atm

c.Kp=2.0 * 10^5

P_{A}=5*10^{-6}atm

P_{B}=0.9999 atm

Explanation:

For the reaction  

A(g)⇌2B(g)

Kp is defined as:

Kp=\frac{(P_{B})^{2}}{P_{A}}

The conditions in the system are:

          A                    B

initial   0                1 atm

equilibrium x       1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.    

Replacing these values in the expression for Kp we get:

Kp=\frac{(1-2x)^{2}}{x}

Working with this equation:

x*Kp=(1-2x)^{2} - -> x*Kp=4x^{2}-4x+1- - >4x^{2}-(4+Kp)*x+1=0

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1

The general expression to solve these kinds of equations is:

x=\frac{-b(+-)*\sqrt{(b^{2}-4ac)}}{2a} (equation 1)

We just take the positive values from the solution since negative partial pressures don´t make physical sense.

Kp = 1.4

x_{1}=\frac{(1.4+4)+\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=1.128

x_{1}=\frac{(1.4+4)-\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=0.2215

With x1 we get a partial pressure of:

P_{A}=1.128 atm

P_{B}=1-2*1.128 = -1.256 atm

Since negative partial pressure don´t make physical sense x1 is not the solution for the system.

With x2 we get:

P_{A}=0.2215 atm

P_{B}=1-2*0.2215 = 0.556 atm

These partial pressures make sense so x2 is the solution for the equation.

We follow the same analysis for the other values of Kp.

Kp=2*10^-4

X1=0.505

X2=0.495

With x1

P_{A}=0.505atm

P_{B}=1-2*0.505 = -0.01005 atm

Not sense.

With x2

P_{A}=0.495atm

P_{B}=1-2*0.495 = 0.00995 atm

X2 is the solution for this equation.  

Kp=2*10^5

X1=50001

X2=5*10^{-6}

With x1

P_{A}=50001atm

P_{B}=1-2*50001=-100001atm

Not sense.

With x2

P_{A}= 5*10^{-6}atm

P_{B}=1-2*5*10^{-6}= 0.9999 atm

X2 is the solution for this equation.  

8 0
3 years ago
Toothpaste contains Sodium fluoride which is used to prevent tooth decay. How many grams are in 1 mole NaF?
nikitadnepr [17]

The answer is 42 grams of NaF are there in 1 mole.

<h3>What is a mole ?</h3>

A mole is defined as 6.022 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance.

Molar Mass , i.e. mass of 1 mole of NaF is sum of molar mass of Na and F

23 + 19

42 grams

Therefore 42 grams of NaF Sodium-fluoride are there in 1 mole.

To know more about mole

brainly.com/question/26416088

#SPJ1

6 0
1 year ago
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