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Mkey [24]
3 years ago
10

Using the fact that at 0.10 M, the absorbance was 0.357; and at 0.20 M, the absorbance was 0.714, the absorptivity (slope) is

Chemistry
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

The answer is "3.57 and 0.07".

Explanation:

Using the slop formula:

=\frac{n_2-n_1}{n_2-n_1}\\\\ =\frac{0.714-0.357}{0.20-0.10} \\\\ = ABSORPTIVITY, \ \ a=3.57 \\\\A= a\times b \times c

Given:

A=0.250

length path b=1  

from calibration it is found that

a=3.57\\\\consentation \ c=\frac{A}{a\times b} \\\\C=\frac{0.250}{3.57\times 1}

   =0.07 \ M

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Solution:- The level of mercury in the atmospheric arm that is the open arm is 83 mm. It indicates the gas pressure is 83 mm higher than the atmospheric pressure.

gas pressure = height of mercury level in open tube in mm + atmospheric pressure

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If we think about sig figs rule then 87.9 should be round to 88 as in addition we go with least number of decimal places. 11 kPa does not have any decimal places and so the gas pressure is 88 kPa.

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4 years ago
Which of the following pieces of laboratory glassware should be used to most accurately measure out a 25.00 ml sample of a solut
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Answer:

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