Imagine a ball is moving on the following horizontal line.
. . . . . . . . . . . . . . . . . . . O. . . . . . . . . . . . . . . . . .
Take right as positive. O is the starting point of the ball. Denote the ball by o.
. . . . . . . . . . . . . . . . . . . O. . . . . . . ... . . o . . . . . .
Assume the ball is moving to the right. It has positive displacement since it is on the right of O, and positive velocity since its positive displacement is increasing.
.ñ
. . . . . . . . . . . . . . . . . . . O. . . . o . . . . . . . . . . . . .
Now the ball is returning to O. It still has positive displacement since its current position is still on the right of O. However, its velocity is negative since its positive displacement is decreasing and the direction of the velocity vector points left, which is the negative side.
By now you should be able to come up with a scenario where the ball has negative displacement and positive velocity.
You can observe the same phenomenon in daily life. Say, as a stretched spring bounces to its starting position, if we let the returning direction be positive, the string has negative displacement since it is on the negative direction, but has positive velocity. Bungee jump can also used to illustrate the phenomenon.
Explanation:
Vnet = 0.4m/s - 3.0m/s = - 2.6m/s
so the man walks 2.6m/s towards the west
We have no way to say what the illustration represents, mainly because
you haven't given us a way to see the illustration.
<span>However, the process that all stars, including our sun, use to continuously
produce energy is nuclear fusion.</span>
Anode
Explanation:
The anode in the gas discharge tube used by Thomson in his experiment was the positively charged electrode.
Using the gas discharge tube, Thomson made the remarkable discovery of cathode rays.
The rays moves from the negatively charged cathode to the positively charged anode. This indicated that the rays carry positive charges.
Some parts of the tube are:
- Cathode - negatively charged electrode
- Power source
- Gas at low pressure
- Outlet to vacuum pump
Learn more:
cathode brainly.com/question/12747250
#learnwithBrainly
Answer:
If a negatively charged balloon is brought near one end of the rod but not in direct contact, then <u>the negative charges on the balloon repel the same amount of negative charges on the end of the rod that is close to the balloon</u>, and the positive charges stay at the balloon-side of the rod. The total charge of the rod is still zero, but the distribution of the charges are now non-uniform.