As the intensity increases the energy increases.
Answer:
C. the energy of the sound wave increases
Answer:
h=17357.9m
Explanation:
The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.
To calculate this, you need to use the barometric formula:

Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.
Furthermore, the specific gas constant is defined by:

Therefore yo can write the barometric formula as:

at the surface of the planet (h =0) the pressure is ![P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}](https://tex.z-dn.net/?f=P_0%5B%5Ctex%5D.%20The%20pressure%20at%20the%20height%20requested%20is%20half%20of%20that%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DP%3D%5Cfrac%7BP_0%7D%7B2%7D)
applying to the previuos equation:

solving for h:
h=17357.9m
Answer:
A. 1.8x10⁵
Explanation:
For this question we have
72km/h = speed
Total mass = 2250kg
Stopped at t = 0.2250s
To get average force acting on this car on collision:
72km/3.6 = 20m|s
Impulse = ∆p
This implies:
F∆t = m∆v
F = m∆v/∆t
= 2250x20/0.250
= 180000
= 1.8x10⁵
Therefore option A is correct.
The wave property is called frequency
Answer:
a) Δx ≈ 8.4 m
b) v ≈ 6.1 m/s
Explanation:
Given:
v₀ = 1.5 m/s
a = 2.1 m/s²
t = 2.2 s
a) Find: Δx
Δx = v₀ t + ½ at²
Δx = (1.5 m/s) (2.2 s) + ½ (2.1 m/s²) (2.2 s)²
Δx ≈ 8.4 m
b) Find: v
v = at + v₀
v = (2.1 m/s²) (2.2 s) + (1.5 m/s)
v ≈ 6.1 m/s