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Anastasy [175]
3 years ago
14

A couple is sitting side-by-side. By what factor should the distance between them be changed by if the attractive force is to be

halved?
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

the distance should be changed by a factor of √2

Explanation:

The attractive force between the couples can be given by Newton's Law of Gravitation:

F =\frac{Gm_1m_2}{r^2}

where,

F = Attractive Force

G = Universal Gravitational Constant

m₁ = mass of the first person

m₂ = mass of the second person

r = distance between them

Now, if we want to halve the force without changing masses, hen:

F' = \frac{1}{2} F = \frac{1}{2} \frac{Gm_1m_2}{r^2}\\\\F' = \frac{1}{2} F = \frac{Gm_1m_2}{(\sqrt{2}r)^2}<u></u>

<u>Hence, it is clear that the distance should be changed by a factor of √2</u>

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80 grams of iron at 100°C is dropped into 200 of water at 20°C contained in an iron vessel of mass 50 gram find the resulting te
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Answer:

the resulting temperature is 23.37 ⁰C

Explanation:

Given;

mass of the iron, m₁ = 80 g = 0.08 kg

mass of the water, m₂ = 200 g = 0.2 kg

mass of the iron vessel, m₃ = 50 g = 0.05 kg

initial temperature of the iron, t₁ = 100 ⁰C

initial temperature of the water, t₂ = 20 ⁰C

specific heat capacity of iron, c₁ = 462 J/kg⁰C

specific heat capacity of water, c₂ = 4,200 J/kg⁰C

let the temperature of the resulting mixture = T

Apply the principle of conservation of energy;

heat lost by the hot iron = heat gained by the water

m_1c_1 \Delta t_1 = m_2c_2\Delta t_2\\\\m_1c_1 (100 - T) = m_2c_2 (T- 20)\\\\0.08 \times 462 (100-T) = 0.2 \times 4,200 (T-20)\\\\36.96 (100-T) = 840 (T-20) \\\\100 - T = 22.72 (T-20)\\\\100-T = 22.72 T - 454.4 \\\\554.4 = 23.72T\\\\T = \frac{554.4}{23.72} \\\\T = 23.37 \ ^0C

Therefore, the resulting temperature is 23.37 ⁰C

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Three 1.5V cells are connected in series in a circuit. What is the total potential difference?
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

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