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Anastasy [175]
3 years ago
14

A couple is sitting side-by-side. By what factor should the distance between them be changed by if the attractive force is to be

halved?
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

the distance should be changed by a factor of √2

Explanation:

The attractive force between the couples can be given by Newton's Law of Gravitation:

F =\frac{Gm_1m_2}{r^2}

where,

F = Attractive Force

G = Universal Gravitational Constant

m₁ = mass of the first person

m₂ = mass of the second person

r = distance between them

Now, if we want to halve the force without changing masses, hen:

F' = \frac{1}{2} F = \frac{1}{2} \frac{Gm_1m_2}{r^2}\\\\F' = \frac{1}{2} F = \frac{Gm_1m_2}{(\sqrt{2}r)^2}<u></u>

<u>Hence, it is clear that the distance should be changed by a factor of √2</u>

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Answer: the options to the questions are

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7 0
3 years ago
A 27-g steel-jacketed bullet is fired with a velocity of 640 m/s toward a steel plate and ricochets along path CD with a velocit
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Answer:

F = - 3.56*10⁵ N

Explanation:

To attempt this question, we use the formula for the relationship between momentum and the amount of movement.

I = F t = Δp

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v = d / t

t = d / v

Given that

m = 26 g = 26 10⁻³ kg

d = 50 mm = 50 10⁻³ m

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t = 8.33 10⁻⁵ s

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This is so, because the bullet bounces the speed sign after the crash is negative

F = m (v-vo) / t

F = 26*10⁻³ (-500 - 640) / 8.33*10⁻⁵

F = - 3.56*10⁵ N

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6 0
3 years ago
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3 years ago
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A phone cord is 4.67 m long. The cord has a mass of 0.192 kg. A transverse wave pulse is produced by plucking one end of the tau
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Answer:

91.017N

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