I’m pretty sure that the answer is B! Hope this helps! :3c
Answer:
ν = 1483.939 m/s
Explanation:
Wave propagation speed (ν):
∴ Wavelength ( λ ) = 4.25 m
∴ Period ( T ) = 1 / f
∴ frequency ( f ) = 349.2 Hz ( s-1 )
⇒ T = 1 / 349.2 s-1
⇒ T = 2.864 E-3 s
⇒ ν = (4.25 m) / (2.864 E-3 s)
⇒ ν = 1483.939 m/s
The Law of Multiple Proportions states that if 2 elements form more than one compound between them, if the mass of one of the elements is fixed, the masses of the other element will be in a ratio of small whole numbers.
In this case, the two elements are Fe and Cl, and the 2 compounds are X and Y. Let us fix the mass of Fe in 1.00 g and analyze what happens with the masses of Cl.
For X:

For Y:

The ratio mCl in X/mCl in Y is 1.27g/1.91g = 0.664 ≅ 2/3. This is a ratio of small whole numbers, which proves the Law of Multiple Proportions.
Answer:
The answer to your question is Abundance N-14 = 99.63%
Abundance N-15 = 0.37%
Explanation:
Data
Average atomic mass = 14.0067 amu
N-14 = 14.003074002
N-15 = 15.00010897
Abundance N-14 = ? x
Abundance N-15 = ? 1 - x
Formula
Average atomic mass = (mass of N-14)x + (mass of N-15)(1 - x)
Substitution
14.0067 = 14.003074002x + 15.00010897(1 - x)
Solve for x
14.0067 = 14.003074002x + 15.00010897 - 15.00010897x
14.0067 - 15.00010897 = 14.003074002x - 15.00010897x
-0.9934 = -0.99703x
x = -0.9934 / -0.99703
x = 0.9963
Conclusion
Abundance N-14 = 0.9963 x 100 = 99.63 %
Abundance N-15 = 1 - 0.9963 = 0.0037 x 100 = 0.37 %
Answer:
Explanation:
The octet rule does not always refer to a stable arrangement of eight valence electrons because there are some element that do not have eight valence electrons yet they are stable. for example;
i) Helium, It has two valence electrons and it is a stable gas.
ii) Boron triflouride (BF3); it has six valence electrons (deficit valence electron) yet it is also stable.
iii) Phosphorus pentachloride (PCl5); it has more than eight valence electron and it is also stable.
For these few reasons it is not always advisable to say octet arrangement refer to stable eight valence electrons.