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harkovskaia [24]
3 years ago
15

Normally, after a chemical reaction you cannot change the products back into their starting form. Ashes cannot become a log agai

n. There are some reactions, however, that can return to their original forms. These reactions are called __________. A. Transformative B. Reversible C. Two-way D. Regressive
I need help..
Chemistry
2 answers:
Lesechka [4]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

A chemical reaction in which products can be changed back into the reactants is known as a reversible reaction.

For example, N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g)

On the other hand, a chemical reaction in which products are not changed back into the reactants then it is known as an irreversible reaction.

For example, AgNO_{3} + NaCl \rightarrow AgCl + NaNO_{3}

Thus, we can conclude that there are some reactions, however, that can return to their original forms. These reactions are called reversible.

shtirl [24]3 years ago
4 0

Answer:

reversible

Explanation:

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When a particle is moving fast it has a lot of kinetic energy in it. ?
Sever21 [200]

Answer:

Random particle motion in liquids and gases is a difficult concept for in temperature, the particles move faster as they gain kinetic energy.

Explanation:

3 0
3 years ago
Write the lewis structure for mgi2. draw the lewis dot structure for mgi2. include all lone pairs of electrons.
viktelen [127]
Lewis Structure is drawn in following steps,

1) Calculate Number of Valence Electrons:
    
# of Valence electrons in Mg  =  2
# of Valence electrons in I      =  7
# of Valence electrons in I      =  7
                                               ---------
Total Valence electrons          =  16

2) Draw Mg as a central atom surround it by two atoms of Iodine.

3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.

Total Valence electrons           16
- Four electrons                    -   4
                                              ----------
                                                  12

4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.

The final lewis structure formed is as follow, 

4 0
3 years ago
What is an atomic nucleus?
Blababa [14]

Answer:

The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom

3 0
3 years ago
A student found the mass of the irregular solid to be 6.4 grams and the volume on the graduated cylinder rose from 6.8 mL to 7.7
Sedaia [141]

Density, Volume and Mass

3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water

level rose to the 37.4 mL mark.

a) Calculate the density of the metal (in g/mL).

b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?

7 0
3 years ago
Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa
kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Where Y_{O_{2} } \\ is the fractional oxygen saturation

{P_{O_{2} } is the partial pressure of oxygen

P_{50} is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

{P_{O_{2} } = 40 mm Hg

P_{50} = 22 mm Hg

h = 3

Putting these values into the equation, we get

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3}  }

Y_{O_{2} } = \frac{64000 }{10648 + 64000  }

Y_{O_{2} } = \frac{64000 }{74648 }

Y_{O_{2} } = 0.86

Hence, the fractional saturation for hemoglobin is 0.86.

4 0
3 years ago
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