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jarptica [38.1K]
3 years ago
10

Gaseous methylamine, CH3NH2, can be classified as __________.(a) a Lewis base only(b) Arrhenius and Brønsted-Lowry bases(c) a Br

ønsted-Lowry base only(d) Arrhenius and Lewis bases(e) Brønsted-Lowry and Lewis bases
Chemistry
1 answer:
Lynna [10]3 years ago
6 0

Answer:

E. Brønsted-Lowry and Lewis bases.

Explanation:

An Arrhenius base is a molecule that when dissolved in water will break down to yield an OH- or hydroxide in solution.

Bronsted-Lowry base refers to any atom or ion capable of accepting or bonding to a free proton in solution.

Lewis Base is an electron pair donor. Also, it is a molecule that attacks another atom with its eldctron is an electron pair donor and a Lewis Base.

So according to the Lewis acid-base concept, amines can donate an electron pair, so they are Lewis bases. Also, Brønsted-Lowry bases can accept a proton to form substituted ammonium ions. So, amines are bases according to both the Lewis and the Brønsted-Lowry base.

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1. Displacement vectors of 10 m west and 14 m west make a resultant vector that is
Iteru [2.4K]

Answer:

B 24 m west I belive that it is the answer

3 0
3 years ago
A quantity of an ideal gas is compressed to half its initial volume. the process may be adiabatic, isothermal or isobaric. the g
JulsSmile [24]

the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.

The process in  which heat is constant is called adiabatic process.

The The process in  which temperature is constant is called isothermal process.

The process in  which pressure is constant is called isobaric process.

The P-V diagram for adiabatic , isothermal and isobaric process is given below.

Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.

learn more about adiabatic process.

brainly.com/question/17192213

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3 0
1 year ago
What is the molarity of a nitric acid solution if 43.13 mL 0.1000 M KOH solution is needed to neutralize 30.00 mL of the acid so
Leno4ka [110]

Answer:

0.144M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

HNO3 + KOH —> KNO3 + H20

From the equation,

nA = 1

nB = 1

From the question given, we obtained the following:

Ma =?

Va = 30.00mL

Mb = 0.1000M

Vb = 43.13 mL

MaVa / MbVb = nA/nB

Ma x 30 / 0.1 x 43.13 = 1

Cross multiply to express in linear form

Ma x 30 = 0.1 x 43.13

Divide both side by 30

Ma = (0.1 x 43.13) /30 = 0.144M

The molarity of the nitric acid is 0.144M

8 0
3 years ago
A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
guapka [62]

Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

6 0
3 years ago
If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?
kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

P(\%) =  \frac{0.1}{0.7}  \times 100 \\  = 14.285714...

We have the final answer as

<h3>14.29 %</h3>

Hope this helps you

4 0
3 years ago
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