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4 years ago

A digital thermometer reads 15 degrees Celsius, what is the uncertainty?

1 answer:

5 0

The uncertainty of the accurate measurement of temperature with a digital thermometer ranges from -1 to +1. So, here in this case, the uncertainty in temperature will be 14 degree to 16 degree Celsius.

<u>Explanation:</u>

The Uncertainty in Measurement

The measurements of objects we observe through our eyes using analog or digital equipment, have some uncertainties. it's not surely the accurate measurement that we observe. Hence, while taking measurements, we must have taken an uncertainty range in the values.

For example, if we take a digital thermometer, which measures the temperature as 15 degree Celsius; it means that the accurate temperature may vary from by the difference of either -1 or + 1 i.e., either 14 degree Celsius or 16 degree Celsius. The same way, the uncertainty range is -0.5 to +0.5 when we use analog thermometer.

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After fixing a flat tire on a bicycle you give the wheel a spin. If its initial angular speed was 6.36 rad/s and it rotated 14.7

lesya692 [45]

To solve this problem we will apply the concepts related to the cinematic equations of angular motion. On these equations, angular acceleration is defined as the squared difference of angular velocity over twice the radial displacement. This is mathematically:

$\alpha = \frac{\omega^2-\omega_0^2}{2\theta}$

Our values are,

$\text{Initial angular velocity} = \omega_0 =6.36 rad/s$

$\text{Final angular velocity} = \omega =0$

$\text{Angular displacement} = \theta = 14.7rev = 29.4\pi rad$

Replacing,

$\alpha = \frac{- 6.36^2}{29.4\pi}$

$\alpha = -0.43rad/s^2$

Therefore the angular acceleration is $-0.43rad/s^2$

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3 years ago

What is the force required to propel an object with mass of 12.0 kg at a rate of 27.0 m/s^2

enyata [817]

Newtons second law --> F = ma

So we have mass which = 12.0

And acceleration = 27.0

So the force = (12)(27)

F = 324 N

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4 years ago

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3. Suppose that an airplane flying 60 m/s, at a height of 300m, dropped a sack of flour (pere the effect

Arlecino [84]

469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.

This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.

The equation of components on the x axis.

$v_{0}x=\frac{x}{t}$ , where x is the distance and Vox the initial velocity before the drop

The equation of components on the y axis.

$y = v_{0}yt+\frac{gt^{2} }{2}$ , where y is the height, and the velocity in y component before the drop is 0, reducing the equation to $y = \frac{gt^{2} }{2}$

Clear t from both the equation of components on the x axis and the y axis:

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Equating both equations and clearing the distance x:

$\frac{x}{v_{0} x}=\sqrt{\frac{2h}{g}}\\x={v_{0} x}\sqrt{\frac{2h}{g}}$

Substituting the values:

$x=60\frac{m}{s} \sqrt{\frac{2(300m)}{9.81\frac{m}{s^{2} } }}=469.24m$

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3 years ago

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solong [7]

Answer:

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Answer:

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