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3 years ago

He __________ uses a series of gears to adjust the output speed of the engine.

Physics

1 answer:

Verizon [17]3 years ago

4 0

Hey ／人 ◕ ‿‿ ◕ 人＼
The answer is transmission

uses a series of gears to transmit power to facilitate changes in speed .

GLAD TO HELP

~~~ ╔͎═͓═͙╗
~~~ ╚̨̈́═̈́﴾ ̥̂˖̫˖̥ ̂ )

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A 17Kg sitting on a shelf has a potential energy of 350J. How high is the shelf? Round your number to the nearest whole number

saul85 [17]

Answer:

${ \bf{potential \: energy = mass \times gravitation \times height}} \\ 350 = 17 \times 10 \times h \\ 350 = 170h \\ height = 2.06 \: metres$

6 0

3 years ago

With what velocity does it hit the ground?

Serggg [28]

That depends on a number of things that we don't know because you haven't told us.

If any of the things on this list changes, then the answer to the question changes:

-- What is "it" ?

-- Was it dropped, thrown, fired, or launched ?

-- From what height above the ground ?

-- With what speed ?

-- In what direction ?

-- What is the acceleration of gravity where this took place ?

-- Did any drag act on it, due to liquid or gas, before it hit the ground ?

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3 years ago

If the ball leaves the projectile launcher at a speed of 2.2 m/s at an angle of 30ᴼ, and the projectile launcher is on a table a

IgorC [24]

Answer: 1.12 m

Explanation:

This situation is related to parabolic motion, hence we can use the following equations:

$y=y_{o}+V_{o}sin \theta t-\frac{g}{2}t^{2}$ (1)

$x=V_{o} cos \theta t$ (2)

Where:

$y=0 m$ is the ball final height (when it hits the ground)

$y_{o}=1.1 m$ is the ball initial height

$V_{o}=2.2 m/s$ is the initial velocity

$\theta=30\°$ is the angle at which the ball was launched

$t$ is the time

$g=9.8 m/s^{2}$ is the acceleration due gravity

$x$ is the horizontal distance the ball travels

Rewriting (1) with the given values:

$0 m=1.1 m+(2.2 m/s)(cos 30\°)t-\frac{9.8 m/s^{2}}{2}t^{2}$ (3)

Multiplying all the eqquation by -1 and rearranging:

$4.9 m/s^{2} t^{2}-1.1 m/s t-1.1 m=0$ (4)

So, since we have a quadratic equation here (in the form of $0=at^{2}+bt+c$ , we will use the quadratic formula to find $t$ :

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ (5)

Where $a=4.9$ , $b=-1.1$ , $c=-1.1$

Substituting the known values and choosing the positive result of the equation, we have:

$t=\frac{-(-1.1)\pm\sqrt{(-1.1)^{2}-4(4.9)(-1.1)}}{2(4.9)}$

$t=0.59 s$ (6)

Now, substituting (6) in (2):

$x=(2.2 m/s)(cos 30\°)(0.59 s)$ (7)

$x=1.12 m$ (8) This is the horizontal distance at which the ball hits the ground.

3 0

4 years ago

An ipod uses a standard 1.7 volt battery. How much resistance is in the circuit if it uses a current of 0.03 amps

natali 33 [55]

Answer:

R = V ÷ I = 1.5V ÷ 0.01A = 150Ω

Explanation:

150 is the answer:)

7 0

3 years ago

two coins lie 1.5 meters apart on a table. they carry identical electric charges. approximately how largeis the charge on each c

BARSIC [14]

The charge on each coin is equal to

Given the following data:

Force = 2.0 Newton

Radius = 1.5 meters

To determine the charge on each coin, we would apply the law of electrostatic forces:

Mathematically, the law of electrostatic forces is given by the formula:

Note: (since the coin carry identical electric charges).

Therefore, the formula becomes:

Making q the subject of formula, we have:

Substituting the given parameters into the formula, we have;

8 0

3 years ago