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saw5 [17]
3 years ago
11

15 points

Physics
1 answer:
Marizza181 [45]3 years ago
6 0
Basaltic magma is the A. The least explosive type of magma.
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While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
Which explains upwelling in the oceans?
Leokris [45]

Winds blowing across the ocean surface push water away. Water then rises up from beneath the surface to replace the water that was pushed away. This process is known as “upwelling.”

Upwelling occurs in the open ocean and along coastlines. The reverse process, called “downwelling,” also occurs when wind causes surface water to build up along a coastline and the surface water eventually sinks toward the bottom.

Water that rises to the surface as a result of upwelling is typically colder and is rich in nutrients. These nutrients “fertilize” surface waters, meaning that these surface waters often have high biological productivity.  Therefore, good fishing grounds typically are found where upwelling is common.

7 0
3 years ago
Can someone help answers these questions? <br> (I attached the pictures)
RoseWind [281]

Nothing works if Switch-3 is open.

-- None

-- A, E, F, G

-- None

-- A, B, E, F, G

-- A, C, D, E, F, G (everything except B)

3 0
3 years ago
Fill in the blanks ....... combine features of both web apps and native apps​
natta225 [31]

Answer:

yvutvuvutvtyvyvtvytvtyvtvytvytvy

3 0
3 years ago
A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel
Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

F=ma

Using the formula

2.88=0.50a

a=\frac{2.88}{0.50}=5.76m/s^2

a=\frac{v-u}{t}

Using the formula

5.76=\frac{v-0}{1.48}

v=5.76\times 1.48=8.5m/s

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0
3 years ago
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