Answer : The correct answer is 1) AlCl₃ - CH₃Cl 2) HNO₃ -H₂SO₄ at room temperature 3) Fuming HNO₃ -H₂SO₄ at 90-100 ⁰ C heat .
I think this reaction is forming 2,4,6- trinitrotoluene from benzene, since the product is not mentioned. Following are the steps to convert Benzene to 2,4,6 trinitrotoluene .
Step 1: Conversion of Benzene to Toluene .
Benzene can be converted to toluene by Friedel Craft Alkylation of benzene . In this reaction reagent AlCl₃ and Ch3Cl is used . Electrophile CH³⁺ is produced which attached on carbon of benzene and formation of Toluene and HCl occur.

Step 2 : Conversion of Toluene to dinitrotoluene.
Dinitritoluene is prepared from toluene by Nitration . This reaction uses Electrophilic substitution mechanism . The reagents used are HNO₃ and H₂SO₄ at room temperature . These reagents produces NO₂⁺ ( nitronium ion ), a electrophile which attacks on C2 and C4 Carbon atoms of Toluene.
Toluene 
Step 3) Conversion of Dinitro toluene to trinitrotoluene.
This reaction is extended nitration of toluene . Further nitration is done in extreme condition . The temperature of reaction is increased to 90- 100 ⁰ C . Due to which there is more production of NO²⁺ ion occurs from HNO₃ -H₂SO₄ and they attack on C6 carbon atom of dinitrotoluene which forms 2,4,6- trinitrotoluene.
Dinitrotoluene 
So over all reaction uses three reagents in order :

Answer:B equals mass divided by volume
Explanation:I got hacks :)
Answer: The mass is 348.8g
Explanation:
We begin by using Avogadro's number to convert the number of molecules of Sodium Hydroxide to moles.
6.02 x 10∧23 molecules of NaOH -------> 1 mole of NaOH
∴ 5.25 x 10∧24 molecules of NaOH -------> 1/ 6.02 x 10∧23 x 5.25 x 10∧24 =
8.72moles.
Having found the number of moles, we then move from moles to gram by using the molar mass of NaOH (i.e the mass of 1 mole of NaOH).
1 mole of NaOH is equivalent to 40g (Molar Mass)
8.72 moles of NaOH would be equivalent to; 40/ 1 x 8.72 = 348.8g
The mass in 5.25 x 10∧24molecules of NaOH is 348.8g
Water can dissolve salt because the positive part of water molecules attracts the negative chloride ions and the negative part of water molecules attracts the positive sodium ions. The amount of a substance that can dissolve in a liquid (at a particular temperature) is called the solubility of the substance.
For an ideal gas, we use the ideal gas equation to relate pressure, volume and temperature changes. It is expressed as:
PV=nRT
For this case, we set V, n as constant.
P/T = nR/V = constant = k
P = kT
P1/T1 = P2/T2
P1/T1 = 2P1 / T2
T2 = 2P1(T1) / P1
T2 = 2T1
Therefore, in order to double the pressure of the system, we need to double the temperature as well at constant volume and number of moles.