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mars1129 [50]
3 years ago
5

In an experiment, zinc chlorate decomposed according to the following chemical equation.

Chemistry
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

The last one is the correct answer!

Explanation:

I just took the test ;)

mote1985 [20]3 years ago
6 0

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of Zn(ClO_3)_2

\text{ Moles of }Zn(ClO_3)_2=\frac{\text{ Mass of }Zn(ClO_3)_2}{\text{ Molar mass of }Zn(ClO_3)_2}=\frac{150g}{232.29g/mole}=\frac{150}{232.29}mole

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

Zn(ClO_3)_2\rightarrow ZnCl_2+3O_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Zn(ClO_3)_2 react to give 3 mole of O_2

So, \frac{150}{232.29} moles of Zn(ClO_3)_2 react to give \frac{150}{232.29}\times \frac{3}{1} moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(\frac{150}{232.29}\times \frac{3}{1})mole\times (31.998g/mole)=\frac{150\times 3\times 31.998}{232.29\times 1}g

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

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When a physical change occurs what cannot be affected as well?
vitfil [10]

Answer:

i believe it is D because the composition does not change

Explanation:

7 0
3 years ago
A certain solution of methylamine has a pOH of 6.8, while a solution of pyridine has a pOH of 6.0. Which solution has a greater
Liono4ka [1.6K]

Answer:

Pyridine solution has a greater concentration of hydroxide ions.

Explanation:

The pOH of the solution is defined as negative logarithm of hydroxide ion concentration in a solution.

pOH=-\log [OH^-]

  • Higher the value of pOH lessor will be the hydroxide ion concentration and higher the concentration of hydrogen ions in the solution .
  • Lower the value of pOH higher will be the hydroxide ion concentration and lower the concentration of hydrogen ions in the solution.

1) The pOH of the methylamine = 6.8

6.8=-\log[OH^-]

[OH^-]=1.5848\times 10^{-7} M

2) The pOH of the pyridine = 6.0

6.0=-\log[OH^-]

[OH^-]=0.000001 M=1.0\times 10^{-6} M

Pyridine solution has a greater concentration of hydroxide ions than the solution of methylamine.

8 0
4 years ago
Read the following chemical equations.
fredd [130]
D) Chlorine is reduced as hydrogen is added whereas Iron is oxidised as Joins with a non hydrogen compound.
8 0
3 years ago
What description best describes both mirrors and lenses?
WITCHER [35]
Mirrors reflect light and lenses refract light.
Mirrors form images by reflecting all light that is incident on their surface, which allows us to see the reflections of objects in mirrors. Lenses, on the other hand, bend light and allow it to pass through them. The bending of light is used to form enlarged images, and for many other purposes as well.
7 0
3 years ago
Read 2 more answers
Write the balanced equation and determine the information requested in each of the following.
Elena L [17]

Answer:

See explanation.

Explanation:

Hello!

In this case, we can proceed as follows:

1. Here, the undergoing chemical reaction is:

C_2H_2+\frac{5}{2} O_2\rightarrow 2CO_2+H_2O

Thus, the moles and mass of water turn out:

n_{H_2O}=20.0kgC_2H_2*\frac{1000gC_2H_2}{1kgC_2H_2} *\frac{1molC_2H_2}{26.04gC_2H_2} *\frac{1molH_2O}{1molC_2H_2}=768molH_2O\\\\m_{H_2O}=768molH_2O*\frac{18.02gH_2O}{1molH_2O}=13,840 gH_2O

2. Here, the undergoing chemical reaction is:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

So the required moles of HCl and the yielded of water are:

n_{CaCO_3}=2.6molHCl*\frac{1molCaCO_3}{2molHCl}=1.3molCaCO_3\\\\ n_{H_2O}=2.6molHCl*\frac{1molH_2O}{2molHCl}=1.3molH_2O

3. Here, the undergoing chemical reaction is:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

Now, we apply each mole ratio obtain:

A.

n_{H_2SO_4}=2.6molAl_2O_3*\frac{3molH_2SO_4}{1molAl_2O_3} =7.8molH_2SO_4

B.

n_{Al_2(SO_4)_3}=2.6molAl_2O_3*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3} =2.6molAl_2(SO_4)_3

Best regards!

4 0
3 years ago
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