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3 years ago

How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water

Physics

1 answer:

Nezavi [6.7K]3 years ago

5 0

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

The computation of the velocity of the water flow is as follows

Here we use the Bernouli equation

As we know that

$V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)} \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}$

= 7.92 m/s

Hence, the velocity of the water flow is 7.92 m/s

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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Suppose that you are taking a course in geometry. You are trying to determine whether two geometric shapes are identical, so you

Nataly_w [17]

Explanation:

Yes, in order to determine whether two geometric figures are identical or not we tend to rotate one of the figure clockwise or anti clock wise mentally. However, in clockwise rotation larger the angel more will be the time taken for instance, it will take longer to rotate 120° than to rotate 40°. Whereas in anti clockwise ration it will be vice versa.

3 0

3 years ago

a flowerpot falls from a windowsill 25m above the sidewalk how fast is the flowerpot moving when it strikes the ground

Mariana [72]

s = 25m

v = ?

a = 9.81m/s²

v² = u² + 2as

v² = 0 + 2x9.81x25

v² = 490.5

v = √490.5

= 22.15m/s

3 0

3 years ago

While driving on a highway, your HMMWV starts to pull to one side. You stop and check your tires – one tire is going flat. There

MrRissso [65]

Answer:

30 miles people hour (mph)

Explanation:

The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.

3 0

3 years ago

Una bola de 1 kg gira alrededor de un circulovrtical en el extremo de un cuerda. El otro extremo de la cuerda esta fijo en el ce

Vladimir79 [104]

Answer:

La diferencia entre las tensiones máxima y mínima es de 19.614 newtons.

Explanation:

Puesto que la bola gira en un círculo vertical, existe claramente una diferencia entre las tensiones debido a la influencia de la gravedad y la tensión que resulta de la aceleración centrípeta experimentada por la masa. La máxima tensión ocurre cuando la bola se encuentra en el nadir (o la sima) del trayecto circular, la cual se describe por la Segunda Ley de Newton:

$T_{max} - m\cdot g = m\cdot \frac{v^{2}}{L}$

En cambio, la mínima tensión aparece cuando la bola se encuentra en el cénit (o la cima) del trayecto circular, descrita por la misma ley de Newton:

$T_{min} + m\cdot g = m\cdot \frac{v^{2}}{L}$

Donde:

$T_{min}$ , $T_{max}$ - Tensiones mínima y máxima, medidas en newtons.

$m$ - Masa de la bola, medida en kilogramos.

$g$ - Constante gravitacional, medida en metros por segundo al cuadrado.

$L$ - Distancia con respecto al eje de rotación, medida en metros.

$v$ - Rapidez tangencial, medido en metros por segundo.

Se elimina la aceleración centrípeta de ambas expresiones por igualación:

$T_{min} + m\cdot g = T_{max} - m\cdot g$

Ahora, la diferencia entre las tensiones máxima y mínima es:

$T_{max} - T_{min} = 2\cdot m \cdot g$

Si $m = 1\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces:

$T_{max} - T_{min} = 2\cdot (1\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$T_{max}-T_{min} = 19.614\,N$

La diferencia entre las tensiones máxima y mínima es de 19.614 newtons.

5 0

3 years ago

Dana is on a train traveling at a speed of 20 km/h. Dana walks from the front of the train to the back of the train at a speed o

dezoksy [38]

Answer:

Diana's speed relative to ground is <u>16 km/h</u> in the direction of motion of train.

Explanation:

Given:

Velocity of train in forward direction is, $v_{t,g}=20\ km/h$

Here, $v_{t,g}\to \textrm{velocity of the train relative to ground.}$

Velocity of Diana relative to train in the backward direction is, $v_{D,t}=-4\ km/h$

Negative sign implies backward motion or motion opposite to the direction of train's motion. Here, Diana is walking from front of train to back. So, Diana is moving in the opposite direction.

Now, we know that, for two bodies 'A' and 'B', velocity of 'A' relative to ground is given as:

$v_{A,g}=v_{B,g}+v_{A,B}$

Therefore, velocity of Diana relative to ground is given as:

$v_{D,g}=v_{t,g}+v_{D,t}$

$v_{D,g}=(20-4)\ km/h$

$v_{D,g}=16\ km/h$

So, Diana's speed relative to ground is 16 km/h in the direction of motion of train.

5 0

3 years ago