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2 years ago

How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water

Physics

1 answer:

Nezavi [6.7K]2 years ago

5 0

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

The computation of the velocity of the water flow is as follows

Here we use the Bernouli equation

As we know that

$V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)} \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}$

= 7.92 m/s

Hence, the velocity of the water flow is 7.92 m/s

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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3 years ago

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2 years ago

Benny wonders why when he presses his finger against a map nothing happens to the map. However if he presses a thumbtack into th

anastassius [24]

Answer: The pressure exerted on a surface by an object increases as the surface area of contact decreases.

Explanation:

Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.

As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!

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3 years ago

To provide the pulse of energy needed for an intense bass, some car stereo systems add capacitors. One system uses a 1.6FF capac

Hoochie [10]

Answer:

Energy stored at 12 volt will be 115.2 J and energy stored at 24 volt will be 460.8 volt

Explanation:

We have given capacitance of capacitor C = 1.6 F

Normal voltage V = 12 volt

And system uses 2 volt to charge the system

We know that energy stored in the capacitor is equal to $E=\frac{1}{2}CV^2$

So energy stored at 12 volt will be equal to $E=\frac{1}{2}\times 1.6\times 12^2=115.2j$

And energy stored at 24 volt will be equal to $E=\frac{1}{2}\times 1.6\times 24^2=460.8j$

So energy stored at 12 volt will be 115.2 j and energy stored at 24 volt will be 460.8 j

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2 years ago

Read 2 more answers