All categories

3 years ago

A gas that has a volume of 28 Liters, a Temperature of 318 K, and an unknown pressure initially

Chemistry

1 answer:

Kobotan [32]3 years ago

8 0

Answer: 25.07 atm

Explanation:

Given that,

Initial Pressure of gas (P1) = ?

Initial Volume of gas (V1) = 28L

Initial Temperature of gas (T1) = 318K

Final pressure of helium = 20 atm

Final volume of gas (V2) = 34L

Final temperature of gas (T2) = 308K

Since pressure, volume and temperature are given, apply the combined gas equation

(P1V1)/T1 = (P2V2)/T2

(P1 x 28L)/318K = (20 atm x 34L)/308K

28L•P1/318K = 680 atm•L/308K

To get P1, cross multiply

28L•P1 x 308K = 680 atm•L x 318K

8624L•K•P1 = 216240 atm•L•K

Divide both sides by 8624L•K

8624L•K•P1/8624L•K = 216240 atm•L•K/8624L•K

P1 = 25.07 atm

Thus, the original pressure of the gas is 25.07 atmosphere

You might be interested in

The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into

Annette [7]

Answer:

period 6

Explanation:

If the lanthanides were inserted into the periodic table, they would go into periodic 6.

Their atomic number is between 57 - 71 from element lanthanum to lutetium.

The elements in this period are 15 in number.
They are also know as elements in the f-block.

The elements that makes up the series are:

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

6 0

3 years ago

Balance this chemical equation. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

larisa86 [58]

The first one have a nice day and good luck

8 0

3 years ago

Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

Maksim231197 [3]

Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

$Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J$

<u>2. Energy to change the liquid to steam at 100ºC</u>

$L=\lambda \times n$

λ = 40.6kJ/mol

n = 10.1g / 18.015g/mol = 0.5606mol

$L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J$

<u>3. Total energy</u>

$1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ$

7 0

3 years ago

Based on the solubility chart, which of the listed salts is the most soluble at 25 degrees Celsius?

VashaNatasha [74]

I think it's Potassium iodide because it has the highest solubility at 25°C.

4 0

3 years ago

Read 2 more answers

Use Appendix C to choose the solution with the lower pH:0.1MBeCl₂ or 0.1MCaCl₂

musickatia [10]

A lower pH means that there are extra hydrogen ions in the liquid, whereas a higher pH indicates fewer hydrogen ions in the liquid. In simple terms, pH is a scale from 1 to 14 that measures the acidity or alkalinity of a liquid.

The hydrated ion undergoes hydrolysis in solution producing `H3O+ . This occurs because the Be-O bond is very strong and so in the hydrated ion and it weakens the 0-H bond. Hence, there is a strong tendency to lose protons. For this particular reason, the aqueous solution of `BeCl_2` is acidic in nature.

<h3>Will baking soda decrease pH?</h3>

Baking soda, also regarded as sodium bicarbonate is naturally alkaline, with a pH of 8 When you add baking soda to your pool water, you will increase both the pH and the alkalinity, improving balance and clarity. Many industrial pool merchandise for elevating alkalinity utilize baking soda as their most important active ingredient.

Learn more about pH here:

<h3>brainly.com/question/22390063</h3><h3 /><h3>#SPJ4</h3>

6 0

1 year ago