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Westkost [7]
2 years ago
11

Please, pretty please help me!

Physics
2 answers:
Andrews [41]2 years ago
8 0

Answer:

umm

Explanation:

1223565 578633 =334675

Harrizon [31]2 years ago
7 0
Hhsjjsjdbdvbr fineee
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Calculate the size of the magnetic field 20 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V
Stells [14]

Answer:

1.5 \times 10^{-5} \mathrm{~T}.

Explanation:

Power carried by the line =P=450 \mathrm{MW}=450 \times 10^{6} \mathrm{~W}

Voltage across the line Volts

Current flowing in the line =i

Size of magnetic field =B

Distance from the line

Formula Used:

Current flowing is given as

i=\frac{P}{\Delta V}

Magnetic field by the current carrying wire is given as

B=\left(\frac{\mu}{4 \pi}\right)\left(\frac{2 i}{r}\right)

Inserting the values

 B=\left(10^{-7}\right)\left(\frac{2(1500)}{(20)}\right) \\
B=1.5 \times 10^{-5} \mathrm{~T}

Conclusion:

Thus, the magnetic field comes out to be 1.5 \times 10^{-5} \mathrm{~T}.

7 0
2 years ago
Weather maps use isobar lines to show weather conditions. Which of the following information is indicated by these lines?
marishachu [46]
A its is high and low pressure areas
4 0
3 years ago
Read 2 more answers
A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power
lara [203]

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

F = 14*6\\F = 84 [N]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

W = F*d

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

W = 84*40\\W = 3360 [J]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

P=W/t\\

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

P=3360/100\\P=33.6[W]

The power is given in watts

3 0
3 years ago
Explain the following defects of a simple electric cell:
eimsori [14]

Answer:

Explanation:

The two major defects of simple electric cells causes current supplied to be for short time. These defects are: polarization and local action.

a. Polarization: This is a defect caused by an accumulation of hydrogen bubbles at the positive electrode of the cell. It can be prevented by the use of vent, using a hydrogen absorbing material or the use of a depolarizer.

b. Local Action: This is the gradual wearing away of the electrode due to impurities in the zinc plate. It can be controlled by the amalgamation of the zinc plate before it is used.

4 0
3 years ago
The current in a resistor is 3.0 A, and its power is 60 W. What is the voltage?
Novosadov [1.4K]

Answer:

20 volts

Explanation:

Use the equation P=VI

60=V(3)

V=20

6 0
2 years ago
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