Answer:
Current, I = 1000 A
Explanation:
It is given that,
Length of the copper wire, l = 7300 m
Resistance of copper line, R = 10 ohms
Magnetic field, B = 0.1 T
![\mu_o=4\pi \times 10^{-7}\ T-m/A](https://tex.z-dn.net/?f=%5Cmu_o%3D4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%5C%20T-m%2FA)
Resistivity, ![\rho=1.72\times 10^{-8}\ \Omega-m](https://tex.z-dn.net/?f=%5Crho%3D1.72%5Ctimes%2010%5E%7B-8%7D%5C%20%5COmega-m)
We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :
![R=\rho \dfrac{l}{A}](https://tex.z-dn.net/?f=R%3D%5Crho%20%5Cdfrac%7Bl%7D%7BA%7D)
![R=\rho \dfrac{l}{\pi r^2}](https://tex.z-dn.net/?f=R%3D%5Crho%20%5Cdfrac%7Bl%7D%7B%5Cpi%20r%5E2%7D)
![r=\sqrt{\dfrac{\rho l}{R\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%5Cdfrac%7B%5Crho%20l%7D%7BR%5Cpi%7D%7D)
![r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%5Cdfrac%7B1.72%5Ctimes%2010%5E%7B-8%7D%5Ctimes%207300%7D%7B10%5Cpi%7D%7D)
r = 0.00199 m
or
![r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m](https://tex.z-dn.net/?f=r%3D1.99%5Ctimes%2010%5E%7B-3%7D%5C%20m%3D2%5Ctimes%2010%5E%7B-3%7D%5C%20m)
The magnetic field on a current carrying wire is given by :
![B=\dfrac{\mu_o I}{2\pi r}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B%5Cmu_o%20I%7D%7B2%5Cpi%20r%7D)
![I=\dfrac{2\pi rB}{\mu_o}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B2%5Cpi%20rB%7D%7B%5Cmu_o%7D)
![I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B2%5Cpi%20%5Ctimes%200.1%5Ctimes%202%5Ctimes%2010%5E%7B-3%7D%7D%7B4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%7D)
I = 1000 A
So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.
M = W/g
mass (m)
weight (W) and strength of gravity (g)
Therefore the mass of the astronaut is 65 kilograms
My guess would be about 10 years because stars are hot balls of light that are reflections from years ago so it would most likely take awhile
Answer: This is not easy lol
Explanation:
Answer:
m = 20,000 kg
Explanation:
Force, ![F=2.5\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2.5%5Ctimes%2010%5E4%5C%20N)
Acceleration of the shark, ![a=1.25\ m/s^2](https://tex.z-dn.net/?f=a%3D1.25%5C%20m%2Fs%5E2)
It is required to find the mass of the shark. Let m is the mass. Using second law of motion to find it as follows :
F = ma
Putting the value of F and a to find m
![m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20,000\ kg](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BF%7D%7Ba%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B2.5%5Ctimes%2010%5E4%7D%7B1.25%7D%5C%5C%5C%5Cm%3D20%2C000%5C%20kg)
So, the shark's mass is 20,000 kg.