Answer:
The average velocity of the entire trip is 42.5 mph east ⇒ answer C
Explanation:
The average velocity of an object is its total displacement divided by
the total time taken.
It is the rate at which an object changes its position from one
place to another.
It is a Vector quantity
A car travels 25.0 miles due east for one hour
Then it travels another 60.0 miles east for an additional hour
We need to find his average velocity of the entire trip
He is travels due east in the whole trip
The total displacement that he travels = 25 + 60 = 85 miles east
He travels the first part in 1 hour and the second part in another hour
The total time for the whole trip = 1 + 1 = 2 hours
The average velocity = total displacement ÷ total time
His average velocity = 85 ÷ 2 = 42.5 miles/hour east
<em>The average velocity of the entire trip is 42.5 mph east</em>
C: 7 candy bars is the answer i am pretty sure
1) Displacement: -49 m, in the negative direction
Explanation:
The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:
In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:
and the direction is negative, in according to the negative sign.
2) Velocity: -3.27 m/s
Explanation:
Velocity is equal to the ratio between the displacement and the time taken:
in this problem, we have:
d = -49 m is the displacement
t = 15 s is the time
therefore, the velocity is
and the direction is negative.
Answer:
<em>The rebound speed of the mass 2m is v/2</em>
Explanation:
I will designate the two masses as body A and body B.
mass of body A = m
mass of body B = 2m
velocity of body A = v
velocity of body B = -v since they both move in opposite direction
final speed of mass A = 2v
final speed of body B = ?
The equation of conservation of momentum for this system is
mv - 2mv = -2mv + x
where x is the final momentum of the mass B
x = mv - 2mv + 2mv
x = mv
to get the speed, we divide the momentum by the mass of mass B
x/2m = v = mv/2m
speed of mass B = <em>v/2</em>