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HACTEHA [7]
3 years ago
9

Sports managers have the potential to earn more than a million dollars per year. True false

Physics
1 answer:
andriy [413]3 years ago
4 0

Answer:

true

Explanation:

hope this helped!

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A car moving at a speed of 20 m/s has a kinetic energy of 200,000 J from that motion. What is the car's mass?
zhenek [66]

Answer:

i think the answer is 1000 kg but i might be wrong

8 0
3 years ago
Obtain the zeroes of polynomial
morpeh [17]

I assume you meant to say

f(x)=2x^4+3x^3-5x^2-9x-3

Given that <em>x</em> = √3 and <em>x</em> = -√3 are roots of <em>f(x)</em>, this means that both <em>x</em> - √3 and <em>x</em> + √3, and hence their product <em>x</em> ² - 3, divides <em>f(x)</em> exactly and leaves no remainder.

Carry out the division:

\dfrac{2x^4+3x^3-5x^2-9x-3}{x^2-3} = 2x^2+3x+1

To compute the quotient:

* 2<em>x</em> ⁴ = 2<em>x</em> ² • <em>x</em> ², and 2<em>x</em> ² (<em>x</em> ² - 3) = 2<em>x</em> ⁴ - 6<em>x</em> ²

Subtract this from the numerator to get a first remainder of

(2<em>x</em> ⁴ + 3<em>x</em> ³ - 5<em>x</em> ² - 9<em>x</em> - 3) - (2<em>x</em> ⁴ - 6<em>x</em> ²) = 3<em>x</em> ³ + <em>x</em> ² - 9<em>x</em> - 3

* 3<em>x</em> ³ = 3<em>x</em> • <em>x</em> ², and 3<em>x</em> (<em>x</em> ² - 3) = 3<em>x</em> ³ - 9<em>x</em>

Subtract this from the remainder to get a new remainder of

(3<em>x</em> ³ + <em>x</em> ² - 9<em>x</em> - 3) - (3<em>x</em> ³ - 9<em>x</em>) = <em>x</em> ² - 3

This last remainder is exactly divisible by <em>x</em> ² - 3, so we're left with 1. Putting everything together gives us the quotient,

2<em>x </em>² + 3<em>x</em> + 1

Factoring this result is easy:

2<em>x</em> ² + 3<em>x</em> + 1 = (2<em>x</em> + 1) (<em>x</em> + 1)

which has roots at <em>x</em> = -1/2 and <em>x</em> = -1, and these re the remaining zeroes of <em>f(x)</em>.

3 0
3 years ago
What happens when the electron moves from the first energy level to the second energy level?
Anuta_ua [19.1K]
Energy is absorbed by the atom.

Emission lines occur only in the case of transitions from higher to lower energy levels in which energy is emitted.
8 0
4 years ago
Read 2 more answers
Using a refracting telescope, you observe the planet Mars when it is 1.95 × 10 11 m from Earth. The diameter of the telescope's
liubo4ka [24]

Answer:

The minimum feature size is 136.6 km.

Explanation:

It is given that,

Distance from planet Mars and Earth is, D=1.95\times 10^{11}\ m

Diameter of the objective lens, d = 0.977 m

We need to find the minimum feature size, on the surface of Mars that your telescope can resolve for you. The expression for resolving distance is given by :

y=\dfrac{1.22D\lambda}{d}\\\\y=\dfrac{1.22\times 1.95\times 10^{11}\times 561\times 10^{-9}}{0.977 }\\\\y=136603.78\ m\\\\y=136.6\ km

So, the minimum feature size is 136.6 km.

8 0
3 years ago
A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg
Dahasolnce [82]

Answer:

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(5 kg) (6 m/s) + (4 kg) (-5 m/s) = (5 kg) v₁ + (4 kg) v₂

10 m/s = 5 v₁ + 4 v₂

Assuming an elastic collision, kinetic energy is conserved.

½ m₁ u₁² + ½ m₂ u₂² = ½ m₁ v₁² + ½ m₂ v₂²

m₁ u₁² + m₂ u₂² = m₁ v₁² + m₂ v₂²

(5 kg) (6 m/s)² + (4 kg) (-5 m/s)² = (5 kg) v₁² + (4 kg) v₂²

280 m²/s² = 5 v₁² + 4 v₂²

Substituting:

v₂ = (10 − 5 v₁) / 4

280 = 5 v₁² + 4 [(10 − 5 v₁) / 4]²

280 = 5 v₁² + (10 − 5 v₁)² / 4

1120 = 20 v₁² + (10 − 5 v₁)²

1120 = 20 v₁² + 100 − 100 v₁ + 25 v₁²

0 = 45 v₁² − 100 v₁ − 1020

0 = 9 v₁² − 20 v₁ − 204

0 = (9 v₁ + 34) (v₁ − 6)

v₁ = -3.78 m/s or 6 m/s

u₁ = 6 m/s, so v₁ = -3.78 m/s.  Solving for v₂:

v₂ = (10 − 5 v₁) / 4

v₂ = 7.22 m/s

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

6 0
3 years ago
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