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3 years ago

14

2) What must be connected for an electrical current to flow in a simple current?

1 answer:

hjlf3 years ago

6 0

2) What must be connected for an electrical current to flow in a simple current?

<em>d.moving magnets,conductors, load to do work </em>

here moving magnets will work as generator and conductors is used as connectors.

5)What is the purpose of a load in a circuit?

<em>c.provide resistance to keep the voltage strong </em>

Load will provide the resistance to the circuit and help to build the voltage across it

6) What cause an electric current from a generator

<em>d.Magnets and conducting wires move near each other </em>

here when magnets move near wires then it will induce the electric current and behaves like generators

7) What do all generators have in common

<em>b.they transform mechanical into electrical energy </em>

They have magnets and rotating coils which will convert magnetic energy to electrical energy

8) How can we measure electrical current

<em>b.the pressure force is voltage;the # of electrons moving is amperes </em>

this voltage and number of electrons will help to calculate current

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Convert the mass to kgs thanks

Natali [406]

Memorize this and you'll be able to do ALL of these: <em>1 kg = 1,000 g</em>

So if you have some grams, divide the number by 1,000 to get kilograms.

1,000 g = 1.000 kg

500 g = 0.500 kg

100 g = 0.100 kg

50 g = 0.050 kg

20 g = 0.020 kg

10 g = 0.010 kg

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3 years ago

Flura [38]

Answer:

about 4 km

Explanation:

15 minutes is a quarter of an hour, so you divide 16km by 4 to get your answer

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A 3858 N piano is to be pushed up a(n) 3.49 m frictionless plank that makes an angle of 31.6 ◦ with the horizontal. Calculate th

uranmaximum [27]

The work done will be equal to the potential energy of the piano at the final position

P.E=m.g.h

.consider the plank the hypotenuse of the right triangle formed with the ground
.let x be the angle with the ground=31.6°
.h be the side opposite to the angle x (h is the final height of the piano)
.let L be the length of the plank

sinx=opposite side / hypotenuse
= h/L

then h=L.sinx=3.49×sin31.6°=0.638m

weight w=m.g
m=w/g=3858/10=385.8kg

Consider Gravity g=10m/s2

then P.E.=m.g.h=385.8kg×10×0.638=2461.404J

then Work W=P.E.=2451.404J

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Hope this helps you.

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tatyana61 [14]

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