Answer:
Explanation:
Let the velocity of projectile be v and angle of throw be θ.
The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m 
considering its vertical displacement 
h = - ut +1/2 g t² 
100 = - vsinθ x 5 + .5 x 9.8 x 5²
5vsinθ =  222.5
vsinθ = 44.5 
It covers 160 horizontally in 5 s 
vcosθ x 5 = 160
v cosθ = 32
squaring and adding 
v²sin²θ +v² cos²θ = 44.4² + 32²
v² = 1971.36 + 1024
v = 54.73 m /s 
 
        
                    
             
        
        
        
The temperature of the gas is 41.3 °C.
Answer:
The temperature of the gas is 41.3 °C.
Explanation:
So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923× atm. Thus, 171000 Pa = 1.6876 atm.
 atm. Thus, 171000 Pa = 1.6876 atm.
We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.
Then substituting all the values in ideal gas equation ,we get
1.6876×50=3.27×0.0821×T
Temperature = 
So the temperature is obtained to be 314.3 K. As 0°C = 273 K, 
Then 314.3 K = 314.3-273 °C=41.3 °C.
Thus, the temperature is 41.3 °C.
 
        
             
        
        
        
The independent variable is the different amount of repellent each person is given. This is because it does not depend on any variable. The dependent variable is what they are measuring, which would be the number of bites on each volunteer. 
I hope this helps! :)
 
        
             
        
        
        
Answer:
25.33 rpm 
Explanation:
M = 100 kg 
m1 = 22 kg 
m2 = 28 kg 
m3 = 33 kg 
r = 1.60 m 
f = 20 rpm 
Let the new angular speed in rpm is f'.
According to the law of conservation of angular momentum, when no external torque is applied, then the angular momentum of the system remains constant.
Initial angular momentum = final angular momentum 
(1/2 x M x r^2 + m1 x r^2 + m2 x r^2 + m3 x r^2) x ω = 
                                   (1/2 x M x r^2 + m1 x r^2 + m3 x r^2 ) x ω'
(1/2 M + m1 + m2 + m3) x 2 x π x f = (1/2 M + m1 + m3) x 2 x π x f'
( 1/2 x 100 + 22 + 28 + 33) x 20 = (1/2 x 100 + 22 + 33) x f'
2660 = 105 x f'
f' = 25.33 rpm
 
        
             
        
        
        
I’m pretty sure it’s true x