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Anna11 [10]
3 years ago
11

suppose the same chest is at rest. you push it horizontally with force of 110N but it does not budge. What is the contact force

on the chest due to the floor
Physics
1 answer:
Radda [10]3 years ago
4 0

Answer:

110 N

Explanation:

When a force is applied on a body and body does not move, it means the body remains at rest.

In this condition, there is a contact force between the body and the floor which is called static friction.

Th static friction force is a self adjusting force and comes into play when the body is at rest.

Here, the applied force is 110 N and the chest is not moving, that means a static friction force is acting between the chest and the floor. This static friction force is the force of contact between the chest and the floor. The static friction force is equal to the applied force when the body does not move.

So, the contact force between the chest and the floor is 100 N.

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Answer:

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Explanation:

a)

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x = stretch of the spring from relaxed length when force "F" is applied = 3 cm = 0.03 m

k = spring constant of the spring

Since the force applied causes the spring to stretch

F = k x

7.50 = k (0.03)

k = 250 N/m

b)

m = mass of the particle attached to the spring = 0.500 kg

Angular frequency of motion is given as

w = \sqrt{\frac{k}{m}}

w = \sqrt{\frac{250}{0.5}}

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Angular frequency is also given as

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22.4 = 2 (3.14) f

f  = 3.6 Hz

T = Time period

Time period is given as

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T = \frac{1}{3.6}

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c)

A = amplitude of motion = 5 cm = 0.05 m

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Answer:

m = 15.15 kg

Explanation:

Newton's Second Law of motion states that when an unbalanced force is applied on a body, an acceleration is produced in it in the direction of force. The component of force along the horizontal direction here, will be given by the Newton's Second Law as:

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