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harkovskaia [24]
2 years ago
6

If a car accelerates at 7.5 mph/s, what would be its final speed after 5.0 seconds if its

Physics
1 answer:
alexgriva [62]2 years ago
4 0

Answer:

87.5mph

Explanation:

Given parameters:

Acceleration  = 7.5mph/s

Starting speed  = 50mph

Time  = 5s

Unknown:

Final speed  = ?

Solution:

Acceleration is defined as the rate of change of velocity with time:

   Acceleration  = \frac{Final speed  - Starting speed }{time }

Insert the parameters and solve;

 7.5  = \frac{Final speed  - 50 }{5 }

  Final speed - 50  = 7.5 x 5

  Final speed  = 7.5 x 5 + 50  = 87.5mph

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The multiple reflection of a single sound wave is a/an
ANTONII [103]

A single reflection, like shouting at the side of a mountain and hearing
your voice come back to you, is an 'echo'.

Multiple reflection, like clapping your hands once inside a large room,
is 'reverberation'.

8 0
3 years ago
What is the period of a 4.12 m long pendulum?
lisov135 [29]
Using the equation for period length, you get an answer of about 4.1 seconds.
8 0
3 years ago
A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.
Mama L [17]

Answer: f_{r} = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

W_{x} = horizontal component of the weight = mgsinФ

W_{y} = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - f_{r} = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8m/s^{2}

f_{r} = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

v^{2} = u^{2} + 2aS

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}

we slot in a into the equation below to get frictional force

mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

f_{r} = 16.49N

4 0
3 years ago
A wave is traveling at 241 m/s. It has a wavelength of 30.0 m. What is its frequency?
Feliz [49]

Answer:

A) 8.03Hz

Explanation:

f = V/λ

Where wavelength( λ )= 30m

Speed (V) =241m/S

f= 241/30=8.03Hz

3 0
3 years ago
Please answer ASAP .
Arisa [49]

Answer:

Explanation:

a = gsinθ

a = 9.8sin30

a = 4.9 m/s²

v² = u² + 2as

v² = 0² + 2(4.9)(10)

v² = 98

v = √98 = 9.8994949...

v = 9.9 m/s

8 0
2 years ago
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