Answer: The answer is D :)
Explanation:
Answer:
LOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOONGGGGGGGGGGGGGGGGGGGGGGGGGGG
Explanation:
I think C or OF2.I sorry if I was wrong.
1) Balanced equation
C3H8 + 5O2 -> 3 CO2 + 4 H2O
2) 0.700 L C3H8
Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio
1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2
0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8
x = 3.500 L O2
3) CO2 produced
1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>
x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2
4) Water vapor produced
1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>
x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O
<u>Answer:</u> The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
<u>Explanation:</u>
For the given chemical equation:
The expression of 
for the given reaction:
We are given:
Putting values in above equation, we get:
To calculate the standard Gibbs free energy, we use the relation:
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
= equilibrium constant in terms of partial pressure = 0.174
Putting values in above equation, we get:
Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
