Answer:
N₂(g) + 2O₂(g) → 2NO₂(g).
Explanation;
Photo-chemical smog is considered to be a new type of air pollution that is basically a mixture of pollutants that are formed when volatile compounds of organic nature (Hydrocarbons) react and Nitrogen oxides (NOx) react with solar radiations of sun and lead to the formation of photochemical smog that looks like a brown haze in the skies of cities.
pounds (VOCs) react to sunlight, creating a brown haze above cities. It tends to occur more often in summer, because that is when we have the most sunlight.
As mentioned in the question, the formation of smog involves a series of reactions:
N2(g) + O2(g)—>2NO(g)
2NO(g) + O2(g)—>2NO2(g)
NON(g) light_» NO(g) + O(g)
O2(g)+O(g)—>Os(9)
NO(g) + O2(g)—>NO2(g) + O2(g)
If we combine all these chemical equations, it gives an answer as:
N₂(g) + 2O₂(g) → 2NO₂(g).
This is because main components involve in the formation of smog is initial N2 and 2 molecules of O2.
Hope it helps!
0.008 ÷ 51.3 = 0.0002
Sig Figs
1
0.0002
Decimals
4
0.0002
Scientific Notation
2 × 10-4
E-Notation
2e-4
Words
zero point zero zero zero two
I HOPE I HELP
Answer:
The compound elucidated from the spectral data is <u>4-methyl penta-2-none</u>
Explanation:
- <u>1700 cm-1 from IR data</u> suspects aldehyde/ketone or carboxylic acid. However,since the peak is not a stretched vibration, it implies an aldehyde or ketone present.
- <u>3 ppm H NMR</u> confirms O-CH3 bond
- <u>24.4 13C NMR</u> confirms CH3-R bond
- 26.4 13C NMR confirms H3C-(R)C(H)-R
- 44.2 13C NMR Confirms C=
- 2126 13C NMR confirms aldehyde C=O bond
<u>The deduced structure is 4-methyl penta-2-one (see attached) </u>given multiple CH3 atoms.
Answer:
answer is gold
Explanation:
bcz gold is having a property of malleable so it can be drawn into thin sheets