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CaHeK987 [17]
2 years ago
10

The hybridisation of the central atom in ICL-2a) sp.b) sp2c) sp3d d)sp3​

Chemistry
1 answer:
allsm [11]2 years ago
6 0

Explanation:

For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.

Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)

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What is the formula of a compound in which element y form ccp lattice and atom x occupy 1/3rd of tetrahedral voids
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Y : CCP : 4 atoms
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3 years ago
The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
aivan3 [116]

Answer:

Molarity=1.22\ M

Explanation:

Given:  

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (19 + 273.15) K = 292.15 K  

Volume = 0.200 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

⇒n = 0.008174 moles

From the reaction shown below:-

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

1 mole of H_2SO_4 react with 2 moles of NaOH

0.008174 mole of H_2SO_4 react with 2*0.008174 moles of NaOH

Moles of NaOH = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

8 0
3 years ago
The last electron in an atom of oxygen is added to a ___ orbital.
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Answer:

A

Explanation:

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O2- is the Lewis ______ in the following reaction
matrenka [14]

O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the O^{2-}is the lewis base which is donating an electron pair to the central atom of SO_3 to form SO_4^{-2}.

Hence, O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

Learn more about the lewis base here:

brainly.com/question/15570523

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