Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron = 
= initial temperature of water = 
Now put all the given values in the above formula, we get:
Therefore, the final equilibrium temperature of the water and iron is, 537.12 K
Pb(C₂H₃O₂)₂ is lead(II) acetate
Pb(C₂H₃O₂)₂ --> Pb²⁺ + C₂H₃O₂²⁻
Lead(II) acetate ionizes in aqueous solution to form lead cation and acetate anion.
The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻
C₂H₃O₂²⁻ or CH₃COO⁻ is called the acetate ion.
Therefore, the correct answer is C₂H₃O₂²⁻
Answer:
1 Joule=0.2390057361 Calorie
789kj=789×0.2390057361×1000
=188575.5257829calorie
Explanation:
Hope u have understand
Answer:
[MgSO₄] = 890 mM/L
Explanation:
In order to determine molarity we need to determine the moles of solute that are in 1L of solution.
Solute: MgSO₄ (10.7 g)
Solvent: water
Solution: 100 mL as volume. (100 mL . 1L / 1000mL) = 0.1L
We convert the solute's mass to moles → 10.7 g / 120.36 g/mol = 0.089 moles
Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M
In order to calculate M to mM/L, we make this conversion:
0.89 mol . 1000 mmoles/ 1 mol = 890 mmoles
