Solve the equation for x

Mathematics

1 answer:

KengaRu [80]3 years ago

7 0

You can do this 2 ways, one is knowing the special right triangles called triplets. An example of a triplet would be 3-4-5 where the largest value is the hypotenuse. In this example, the other 2 sides are 3 and 4 and the missing side is the hypotenuse, so using the knowledge of triplets, we can find that the hypotenuse is 5.

algebraically, we can use the Pythagorean theorem; a^2+b^2=c^2 where a and b are the opposite and adjacent and where c is the hypotenuse. We can then substitute in the values to get : 3^2 + 4^2 = c^2. When simplified, we get 9+16=c^2. Simplify further, and get 25=c^2. Now we Square root both sides to solve for C. Finally, we get C=5. Your missing side is 5.

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Find the probability of at least 2 girls in 8 births. assume that male and female births are equally likely and that the births

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At least two girls means either 2, 3 ... or 8 girls.
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Continue simplifying:
$C_8^2+...+C_8^8=2^8-C_8^1=2^8-8=248\\\text{We deduce the probability of the event "at least two girls in birth ":}\\0.0039\times248=0.96\\\text{The above probability (0.96) means that the event is very likely}$

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Katarina [22]

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Read 2 more answers

H(x) = x3 + 7<br> Determine whether the function is one-to-one.

zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

passes the vertical line test to make sure it is indeed a function, and

also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

$h\left(x\right)\:=\:x^3\:+\:7$

Have a look at the attached graph.

The red portion represents the graph of the function $h\left(x\right)\:=\:x^3\:+\:7$ .

The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is indeed a function.

The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.