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abruzzese [7]
3 years ago
10

The particles that are found in the nucleus of an atom are

Physics
1 answer:
kvv77 [185]3 years ago
8 0

Answer: Electrons are the smallest of the three particles that make up atoms. Electrons are found in shells or orbitals that surround the nucleus of an atom

Explanation: hope this helps

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Molecules can be made of atoms of__?
defon

the third answer is right.

8 0
3 years ago
Read 2 more answers
A 5.0-kg bar of lead is placed inside a 12-L chamber filled with helium gas. The temperature of the lead and helium is the same.
Pavlova-9 [17]

As the temperature of the lead and helium is the same. Thus the average kinetic energy is also the same for lead and helium.

Reason:

It is given that a 5.0-kg bar of lead is placed inside a 12-L chamber filled with helium gas. The temperature of the lead and helium is the same. It is required to compare the average kinetic energy of the lead atoms and helium atoms.

The average kinetic energy is calculated as, K=\frac{3}{2} \frac{R}{N} T.

Here K is the average kinetic energy,  R is the gas constant, N is the Avogadro's number, and T is the temperature.

As the temperature is the same for both lead and helium. As a result, the average kinetic energy is also the same for lead and helium.

Learn more about average kinetic energy here,

brainly.com/question/1599923

#SPJ4

4 0
2 years ago
Instruments in an airplane which is in level flight indicate that the velocity relative to the air (airspeed) is 180.00 km/h and
snow_lady [41]

Answer:

Explanation:

From the given information:

The coordinate axis is situated in the east and north direction.

So, the north will be the  y-axis and the east will be the x-axis

Similarly, the velocity of the plane in regard to the air in the coordinate system will be v_{P/A} = v( cos \theta \ i + sin \theta \ j)

where:

v_{P/A} = velocity of the plane in regard to the air

v = velocity

θ =  angle of inclination of the plane with respect to the horizontal

replacing v = 180 km/ and θ = 20° in above equation, then:

The velocity of the airplane in the coordinate system as:

v_{P} = v_o( cos \phi \ i + sin \phi \ j)

where;

v_p = velocity of the airplane

v_o = velocity

∅ = angle of inclination with regard to the base axis;

Then; replacing  v_o  = 150 km/h and ∅ = 30°

Therefore, the velocity of the plane in the system is :

v_p = v_A + v_{P/A}

v_A=  v_P  -v_{P/A}   --- (1)

v_A= ( 150 cos 30° - 180 cos 20°)i + ( 150 sin 30° - 180sin 20°)j

v_A= (-39.24 km/h)i + (13.44 km/h) j

The magnitude is:

v_A= (-39.24 km/h)i + (13.44 km/h) j

|v_A|^2 = \sqrt{ (-39.24 km/h)^2+ (13.44 km/h)^2}

v_A = 41.48 km/h

The airplane is moving at an angle of the inverse tangent to the abscissa and ordinate.

The angle of motion is:

tan θ = 39.24/13.44

tan θ = 2.9

θ  = tan ^{-1} (2.9)

θ  =  70.97°

The angle of motion is  70.97° from west of north with a velocity of 41.48 km/h.

5 0
3 years ago
It was once recorded that a Jaguar
Artyom0805 [142]

Answer:

71.85 m/s

Explanation:

Given the following :

Length of skid marks left by jaguar (s) = 290 m

Skidding Acceleration (a) = - 8.90m/s²

Final velocity of jaguar (v) = 0

Speed of Jaguar before it Began to skid =?

Hence, initial speed of jaguar could be obtained using the formula :

v² = u² + 2as

Where

v = final speed of jaguar ; u = initial speed of jaguar(before it Began to skid) ; a = acceleration of jaguar ; s = distance /length of skid marks left by jaguar

0² = u² + (2 × (-8.90) × 290)

0 = u² + (-5,162)

u² = 5162

Take the square root of both sides

u = √5162

u = 71.847 m/s

u = 71.85m/s

6 0
3 years ago
A crate is sliding on the floor. If there is a total force acting on the crate in the same direction as it is sliding, the crate
Leto [7]

But we do not know whether the force is pushing or pulling (the same direction (both forces are parallel) but: .........[ ]<-F-- or .......[ ]--F-->). I suppose the correct answer is B

7 0
3 years ago
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