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2 years ago

When a 1.7 m tall man stands, his brain is 0.5 m above his heart.

Physics

1 answer:

Lady_Fox [76]2 years ago

5 0

Answer:

9.54 Kpa

Explanation:

Given :

Pheart = 13.3 * 10^3

Density of blood (ρ) = 1060 kg/m³

Difference in height of brain and heart in standing position = - 0.5

Difference in height of Brain a d heart in bending position = 0.4

g = acceleration due to gravity = 10 m/s²

Blood pressure of brain in standing position:

Pheart + ρ*g(-0.5)

13.3 * 10^3 + 1060 * 10 * - 0.5

13300 - 5300 = 8000 pascal = 8Kpa

Blood pressure of brain in bending position:

Pheart + ρ*g(0.4)

13.3 10^3 + 1060 * 10 * 0.4

13300 + 4240 = 17540 Pa = 17.54 Kpa

17.54Kpa - 8Kpa

= 9.54 Kpa

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Which substance is a greenhouse gas that is emitted by human activities, is the most widespread, and remains in the air the long

e-lub [12.9K]

Answer:

I am not really sure, but it is probably Carbon Dioxide

Explanation:

3 0

3 years ago

Read 2 more answers

You move a 25 N object 5 meters. How much work did you do ?

olga55 [171]

The answer is 125 Joules

The first thing to take note of is the work equation: W=F×D

Since we already have our force and our distance that will help make this problem easier.

So, W=25*5

W=125

Therefore, our answer is 125 Joules since work is measured in joules

Hope this helped!! :)

3 0

2 years ago

Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp

slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

$Q=Av$

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

$Q=1.20 m^3/s$

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

$A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2$

So we can re-arrange the equation to find the speed of the water:

$v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s$

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

$Q_1 = Q_2\\A_1 v_1 = A_2 v_2$

where we have

$A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s$

and where $A_2$ is the cross-sectional area of the pipe at the second point.

Solving for A2,

$A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2$

And finally we can find the radius of the pipe at that point:

$A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m$

6 0

2 years ago

Ket [755]

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

3 0

2 years ago

If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:

GenaCL600 [577]

The frequency of the wheel is given by:
$f= \frac{N}{t}$
where N is the number of revolutions and t is the time taken. By using N=100 and t=10 s, we find the frequency of the wheel:
$f= \frac{100}{10 s}=10 s^{-1}$

And now we can find the angular speed of the wheel, which is related to the frequency by:
$\omega=2 \pi f=2 \pi (10 s^{-1})=62.8 s^{-1}$

6 0

3 years ago