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kondaur [170]
3 years ago
12

When a 1.7 m tall man stands, his brain is 0.5 m above his heart.

Physics
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

9.54 Kpa

Explanation:

Given :

Pheart = 13.3 * 10^3

Density of blood (ρ) = 1060 kg/m³

Difference in height of brain and heart in standing position = - 0.5

Difference in height of Brain a d heart in bending position = 0.4

g = acceleration due to gravity = 10 m/s²

Blood pressure of brain in standing position:

Pheart + ρ*g(-0.5)

13.3 * 10^3 + 1060 * 10 * - 0.5

13300 - 5300 = 8000 pascal = 8Kpa

Blood pressure of brain in bending position:

Pheart + ρ*g(0.4)

13.3 10^3 + 1060 * 10 * 0.4

13300 + 4240 = 17540 Pa = 17.54 Kpa

17.54Kpa - 8Kpa

= 9.54 Kpa

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Mamont248 [21]

Answer:

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Explanation:

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3 0
3 years ago
From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of
alexandr1967 [171]

Answer:

The  value is  h  = 11930 \ m

Explanation:

From the question we are told that

    The  temperature is  T  =  300 \  K

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        v  =  \sqrt{\frac{3 *  R  *  T }{M} }  =  \sqrt{ 2 *  g  *  h }

Here  R is the gas constant with a value  R  =  8.314 \  J\cdot K^{-1} \cdot \  mol^{-1}

    M  is the molar mass of oxygen molecule with value M  =  0.032 \  kg /mol

So  

     \frac{3 *  8.314   *  300 }{0.032}   =  2 *  9.8  *  h

=>    h  = 11930 \ m

   

4 0
3 years ago
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gizmo_the_mogwai [7]
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7 0
3 years ago
A 60 kg man jumps down from a 0.8 m table. What is the speed when he
Rom4ik [11]

Answer: Speed = 4 m/s

Explanation:

The parameters given are

Mass M = 60 kg

Height h = 0.8 m

Acceleration due to gravity g= 10 m/s2

Before the man jumps, he will be experiencing potential energy at the top of the table.

P.E = mgh

Substitute all the parameters into the formula

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As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.

When hitting the ground,

K.E = P.E

Where K.E = 1/2mv^2

Substitute m and 470.4 into the formula

470.4 = 1/2 × 60 × V^2

V^2 = 470.4/30

V^2 = 15.68

V = square root (15.68)

V = 3.959 m/s

Therefore, the speed of the man when hitting the ground is approximately 4 m/s

4 0
3 years ago
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