Answer:
C. x=3 and y=−6
Step-by-step explanation:
Step: Solvex−2y=15for x:
x−2y=15
x−2y+2y=15+2y(Add 2y to both sides)
x=2y+15
Step: Substitute2y+15forxin2x+4y=−18:
2x+4y=−18
2(2y+15)+4y=−18
8y+30=−18(Simplify both sides of the equation)
8y+30+−30=−18+−30(Add -30 to both sides)
8y=−48
8y8=−488(Divide both sides by 8)
y=−6
Step: Substitute−6foryinx=2y+15:
x=2y+15
x=(2)(−6)+15
x=3(Simplify both sides of the equation)
Answer:
x=3 and y=−6
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given

The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.

Slope intercept form is:

Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation

Putting the values of b and m

Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
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Answer:
The length of the line is PQ as this line is parallel to the x - axis. So, the length of the line is the summation of 10 from second quadrant and 20 from first quadrant. So, the sum is 30. Hence the length of the line is 30 units.
Step-by-step explanation:
The length of a line segment can be measured by measuring the distance between its two endpoints. It is the path between the two points with a definite length that can be measured. Explanation: On a graph, the length of a line segment can be found by using the distance formula between its endpoints.
Answer:
true
Step-by-step explanation:
Answer:
units or 14.2 units (rounded to the nearest tenth)
Step-by-step explanation:
To find the distance between a pair of two points, use the distance formula
. Substitute the x and y values of (-1,-2) and (8,9) into the formula and simplify:
So, as an exact answer, the distance is
units.
(To find the decimal approximate of that answer, enter it into a calculator. This would make the decimal approximate 14.2 units, when rounded to the nearest tenth.)