1. find our slope: y2 - y1/ x2- x 1
-9 + 4= -5
2 - 2 = 0
m = 0
2. now we need to use our point-slope form to find our y intercept
point-slope form: y - y1 = m(x - x1)
y + 4 = 0(x - 2)
distribute:
y + 4 = 0x
3. get y by itself
y + 4 - 4 = y
0x - 4 = 0x - 4
4. write in slope-intercept form:
y = 0x - 4
OR
y = -4
Answer:
b
Step-by-step explanation:
Answer:
The center is (2,8)
Step-by-step explanation:
The equation of a circle is written as
(x-h)^2+ (y-k)^2 = r^2
where ( h,k) is the center and r is the radius
(x-2)^2+(y-8)^2=33
The center is (2,8) and the radius is sqrt(33)
The equivalent expression is 5^(4) * 3^(-10)
<h3>How to determine the equivalent expression?</h3>
The statement is given as:
five raised to the negative second power times three raised to the fifth power end quantity all raised to the negative second power
Rewrite properly as:
(5^-2 * 3^5)^-2
Expand the expression by multiplying the exponents
So, we have:
5^(-2 -2) * 3^(5 *-2)
Evaluate the products
5^(4) * 3^(-10)
Hence, the equivalent expression is 5^(4) * 3^(-10)
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Answer:

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Step-by-step explanation:
We can find the slope through two points.
m = (y2 - y1)/(x2 - x1)
m = (4 - -5)/(4 - -8)
m = 9/12 = 3/4
The slope of the line is 3/4.
Slope-intercept form of a line is y=mx+b. Where m is the slope and b is the y-intercept.
y = 3/4x + b
A point on the line is (4, 4). x = 4 and y =4.
4 = 3/4(4) + b
4 = 3 + b
b = 1
The y-intercept is 1.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)