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3 years ago

I know the answers, just need step by step work!! If you do both, I will crown ya (:

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

Step-by-step explanation:

Y = 4x2 - 8x - 32

First we will multiply 32 by 4 = 128

Then factors of. 128

4x2 - 16x + 8x - 32

4x(x - 4) + 8(x - 4)

(4x +8) (x-4)

4(x + 2) and (x - 4) are the factors

2 y = 4x2 - 4x - 360

First we will multiply 360 by 4 = 1440

Then factors of 1440

Y = 4x2 - 40x + 36x - 360

4x (x - 10) + 36(x - 10)

(4x + 36) (x - 10)

4(x + 9) (x - 10) are the factors

Zigmanuir [339]3 years ago

5 0

F in the chats for MIBO

You might be interested in

Pleaaseeeee helpppp ASAPPPP

WINSTONCH [101]

Answer:

It would be 11

Step-by-step explanation:

If you look at the 2 x 11 = 22

and that goes on with it on 7 and 9.

Hope this helps!!

4 0

3 years ago

Please help!!! I’ll make you Brainliest

Alona [7]

The answer is A.<span>C(n)=0.50n-0.3; $9.70</span>

4 0

4 years ago

Read 2 more answers

Express answer in exact form.

Ratling [72]

Area of circle = πr²
= 64π
The cord will subtend a semicircle of diameter 8", radius 4". The area of this semicircle:
1/2 πr²
= 0.5 x 4² x π
= 8π
Area of larger region = area of circle - area of semicircle
= 64π - 8π
= 56π inch²

5 0

3 years ago

Read 2 more answers

Professor Andrews found that as the number of days absent increases, students' grades decrease. Professor Andrews has found:

n200080 [17]

Answer:

The function relating student absent days to grades has a negative slope (grades decrease as absences increase).

Step-by-step explanation:

There isn't much information in the question, but here are a couple of observations. Prof. Andrews found:

The function relating student absent days to grades has a negative slope (grades decrease as absences increase).
Evidence suggesting his lectures do convey useful information
Students don't enjoy his class

Just kidding on the last 2, but all statements could be valid based on what little information is provided.

3 0

3 years ago

Guys please help me to do these!!!! im tryin’ my best but it’s so hard

Eduardwww [97]

Answer:

Step-by-step explanation:

∠ACB=6 x°

∠DCE=30°

6x=30°-----------------divide both sides by 6

x=30°/6= 5°

∠BCE=180°-30°=150°----------------sum of angles on a straight line

∠ABD=(4+5x)°

∠CBD=(x+2)°

(4+5x)°+(x+2)°=180°-----------sum of angles on a straight line

4+5x+x+2=180°----------------collect like terms

6x+6=180°

6x=180°-6°

6x=174°------------divide by 6 both sides

x=174°÷6= 29°

∠ABD=4+5x=4+(5*29)= 4+145=149°

∠CBD= x+2=29°+2°=31°

BE bisects ∠ABE=(3x+1)°

m∠DBA=(8x-14)°

1/2 (m∠DBA)° = m∠ABE

1/2(8x-14)°=(3x+1)°

(4x-7)°=(3x+1)°

4x-7=3x+1

4x-3x=7+1-------------collecting like terms

x=8°

m∠ABE=(3x+1)°=(3*8+1)=24+1=25°

m∠DBA=(8x-14)°= (8*8-14)°=(64-14)=50°

∠ADE=∠CDG

50+3x-y=x+2x-16------------collect like terms

50+16-y=x+2x-3x

66-y=3x-3x

66°=y

∠ADC +∠ADB+∠BDE

90°+50°+(3x-y)°=180°

140°+(3x-y)°=180°

3x-66°=180°-140°

3x=40°+66°

3x=106°-----------divide both sides by 3

x=106°÷3= 35.33°

∠FDG=(2x-16)°= (2×35.33° - 16° )= 54.67°

∠BDE = (3x-y)°= (3×35.33°-66°)= 105.99-66=39.99°

∠ABD+∠DBC=90°

(6x+4)°+32°=90°

(6x+4)°=90°-32°

6x+4=58°

6x=58°-4°

6x=54°

x=54°÷6=9°

∠ABD= (6x+4)°+32°

∠ABD= (6×9 +4)°+32°

∠ABD= (54°+4°) + 32°

∠ABD=58°+32°=90°

∠AED=∠CEB

(3x+5)°=(4y-15)°------------------form equation of equality

3x+5=4y-15

5+15=4y-3x

20=4y-3x------------------------------(1)

∠AEC=∠DEB

(y+20)°=(x+15)°

y+20=x+15

20-15=x-y

5°=x-y

5+y=x----------------------------(2)

Use equation (2) in equation (1)

20=4y-3x

20=4y-3(5+y)

20=4y-15-3y

20+15=4y-3y

35°=y

Solve for x

x=5+y=5°+35°=40°

∠AED=(3x+5)°=(3×40 +5 )=120+5=125°

∠AEC= (y+20)°= 35° + 20° =55°

8 0

3 years ago